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北美退伍军人节(Veterans Day),12 日无更新
arXiv 2212.04565math.CO
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Grundy控制强积猜想的一个证明

A Proof of the Grundy domination strong product conjecture

Rebekah Herrman, Stephen G. Z. Smith

摘要:

单图$G = (V,E)$的Grundy控制数是最长的唯一顶点序列$S = (v_1, \ldots, v_k)$,$v_i \in V$的长度,它满足每个$i \in [k]$的性质$N[v_i] \setminus \cup_{j=1}^{i-1}N[v_j] \neq \emptyset$。这里,是$N(v) = \{u : uv \in E\}$和$N[v] = N(v) \cup \{v\}$。本文证明了最近关于两个图的强积的Grundy控制数的一个猜想。然后,我们讨论了这个结果与图的强积的迫零数的关系。

英文摘要:

The Grundy domination number of a simple graph $G = (V,E)$ is the length of the longest sequence of unique vertices $S = (v_1, \ldots, v_k)$, $v_i \in V$, that satisfies the property $N[v_i] \setminus \cup_{j=1}^{i-1}N[v_j] \neq \emptyset$ for each $i \in [k]$. Here, $N(v) = \{u : uv \in E\}$ and $N[v] = N(v) \cup \{v\}$. In this note, we prove a recent conjecture about the Grundy domination number of the strong product of two graphs. We then discuss how this result relates to the zero forcing number of the strong product of graphs.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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