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arXiv 2107.09162math.COmath.SP
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关于树的Laplacian能量的一个猜想

On a conjecture of Laplacian energy of trees

Hilal A. Ganiea, Bilal A. Rather, S. Pirzada

摘要:

设$G$是一个简单图,其顶点为$n$,边为拉普拉斯特征值$μ_1, μ_2, \dots, μ_{n-1},μ_n=0$ .拉普拉斯能量$LE(G)$定义为$LE(G)=\sum_{i=1}^{n}|μ_i-\overline{d}|$,其中$\overline{d}=\frac{2m}{n}$是$G$的平均度。Radenković和Gutman证明了在所有$n$阶树中,路径图$P_n$具有最小的拉普拉斯能量。设$ \mathcal{T}_{n}(d) $是直径为$ d $的$n$阶树族。本文证明了任意树$T\in \mathcal{T}_{n}(4)$的Laplacian能量大于$P_n$的Laplacian能量,从而证明了关于所有直径为$4$的树的Laplacian能量的猜想.我们还证明了猜想的真实性,所有树的非悬垂顶点的数目至多$\frac{9n}{25}-2$。此外,我们给出了一些充分条件的猜想成立的树的顺序$n$。

英文摘要:

Let $G$ be a simple graph with $n$ vertices, $m$ edges having Laplacian eigenvalues $μ_1, μ_2, \dots, μ_{n-1},μ_n=0$. The Laplacian energy $LE(G)$ is defined as $LE(G)=\sum_{i=1}^{n}|μ_i-\overline{d}|$, where $\overline{d}=\frac{2m}{n}$ is the average degree of $G$. Radenković and Gutman conjectured that among all trees of order $n$, the path graph $P_n$ has the smallest Laplacian energy. Let $ \mathcal{T}_{n}(d) $ be the family of trees of order $n$ having diameter $ d $. In this paper, we show that Laplacian energy of any tree $T\in \mathcal{T}_{n}(4)$ is greater than the Laplacian energy of $P_n$, thereby proving the conjecture for all trees of diameter $4$. We also show the truth of conjecture for all trees with number of non-pendent vertices at most $\frac{9n}{25}-2$. Further, we give some sufficient conditions for the conjecture to hold for a tree of order $n$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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