arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 1507.08022math.CO
收藏

任意连通图的线图生成树个数的表达式

Expression for the Number of Spanning Trees of Line Graphs of Arbitrary Connected Graphs

Fengming Dong, Weigen Yan

摘要:

对于任何图$G$,设$t(G)$是$G$的生成树的数目,$L(G)$是$G$的线图,并且对于任何非负整数$r$,$S_r(G)$是通过将每个边$e$替换为连接$e$两端的长度为$r+1$的路而从$G$获得的图。本文用组合方法得到了$t(L(S_r(G)))$在$G$生成树中的表达式。这个结果推广了关于$t(L(S_r(G)))$与$t(G)$之间关系的一些已知结果,并给出了一个显式表达式$t(L(S_r(G)))=k^{m+s-n-1}(rk+2)^{m-n+1}t(G)$,如果$G$的阶为$n+s$,大小为$m+s$,其中$s$的顶点的度为$1$,其它顶点的度为$k$ .因此,我们证明了一个猜想,$t(L(S_1(G)))$,这样的图$G$。

英文摘要:

For any graph $G$, let $t(G)$ be the number of spanning trees of $G$, $L(G)$ be the line graph of $G$ and for any non-negative integer $r$, $S_r(G)$ be the graph obtained from $G$ by replacing each edge $e$ by a path of length $r+1$ connecting the two ends of $e$. In this paper we obtain an expression for $t(L(S_r(G)))$ in terms of spanning trees of $G$ by a combinatorial approach. This result generalizes some known results on the relation between $t(L(S_r(G)))$ and $t(G)$ and gives an explicit expression $t(L(S_r(G)))=k^{m+s-n-1}(rk+2)^{m-n+1}t(G)$ if $G$ is of order $n+s$ and size $m+s$ in which $s$ vertices are of degree $1$ and the others are of degree $k$. Thus we prove a conjecture on $t(L(S_1(G)))$ for such a graph $G$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑