arXivDaily arXiv每日学术速递 周一至周五更新
北美退伍军人节(Veterans Day),12 日无更新
arXiv 0705.4256math.NTmath.CA
收藏

有限域中的和与积:一个积分几何观点

Sums and products in finite fields: an integral geometric viewpoint

Derrick Hart, Alex Iosevich

摘要:

证明了若$A \subset {\Bbb F}_q$使得$$|A|>q^{{1/2}+\frac{1}{2d}},$$则$${\Bbb F}_q^{*} \subset dA^2=A^2+...+A^2 d \text{times},$$,其中$$A^2=\{a \cdot a': a,a' \in A\},$$和${\Bbb F}_q^{*}$表示有限域${\Bbb F}_q$的乘法群.特别地,如果$|A|>q^{3/4}$,我们用$A^2+A^2$覆盖${\Bbb F}_q^{*}$。利用${\Bbb F}_q^d$的几何性质、超平面上的平均性质以及特征和的正交性质,证明了如果$$|A| \ge C_{size}^{\frac{1}{d}}q^{{1/2}+\frac{1}{2(2d-1)}},$$,则$$|dA^2| \ge q \cdot \frac{C^2_{size}}{C^2_{size}+1}.$$.特别是,我们看到,使用的运营商是在欧几里德设置$L^2$平滑导致非平凡的算术后果的上下文中的有限域。

英文摘要:

We prove that if $A \subset {\Bbb F}_q$ is such that $$|A|>q^{{1/2}+\frac{1}{2d}},$$ then $${\Bbb F}_q^{*} \subset dA^2=A^2+...+A^2 d \text{times},$$ where $$A^2=\{a \cdot a': a,a' \in A\},$$ and where ${\Bbb F}_q^{*}$ denotes the multiplicative group of the finite field ${\Bbb F}_q$. In particular, we cover ${\Bbb F}_q^{*}$ by $A^2+A^2$ if $|A|>q^{3/4}$. Furthermore, we prove that if $$|A| \ge C_{size}^{\frac{1}{d}}q^{{1/2}+\frac{1}{2(2d-1)}},$$ then $$|dA^2| \ge q \cdot \frac{C^2_{size}}{C^2_{size}+1}.$$ Thus $dA^2$ contains a positive proportion of the elements of ${\Bbb F}_q$ under a considerably weaker size assumption.We use the geometry of ${\Bbb F}_q^d$, averages over hyper-planes and orthogonality properties of character sums. In particular, we see that using operators that are smoothing on $L^2$ in the Euclidean setting leads to non-trivial arithmetic consequences in the context of finite fields.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑