arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 2005.13870math.NT
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一类复双二次域中的积分平方和

Sums of Integral Squares In Certain Complex Bi-quadratic Fields

Srijonee Shabnam Chaudhury

摘要:

设K是代数数域,O_K是它的整数环.设S_K是O_K中的元素集合,它们是O_K中的平方和,s(O_K)是表示O_K中-1所需的最小平方数。设g(S_K)是最小正整数t,使得S_K中的每个元素都是O_K中的t个平方和。这里K是由m和-n的平方根在有理数域上生成的,其中m同余3 mod 4和n同余1 mod 4是两个不同的无平方因子的正整数,我们证明了$ S_K= O_K.我们还证明了g(O_ K)小于或等于s(O_K)+1或s(O_K)+2。应用这一点,我们证明了如果s(O_K)=2,则g(O_K)=3。这项工作是张和纪最近发起的一项研究的继续。

英文摘要:

Let K be an algebraic number field and O_K be its ring of integers. Let S_K be the set of elements in O_K which are sums of squares in O_K and s(O_K) the minimal number of squares necessary to represent -1in O_K. Let g( S_K ) be the smallest positive integer t such that every element in S_K is a sum of t squares in O_K. Here K is generated over field of rational number by square root of m and -n , where m congruent 3 mod 4 and n congruent 1 mod 4 are two distinct positive square free integers, we prove that $ S_K= O_K. We also prove that g(O_ K) less or equals to s(O_K)+1 or s(O_K)+2. Applying this, we shows that if s(O_K)=2, then g(O_K)=3. This work is continuation of a recent study initiated by Zhang and Ji .

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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