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arXiv math/0111257math.CO
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正则和几乎正则图的拓扑数

The domatic number of regular and almost regular graphs

Raphael Yuster

摘要:

图$G$的domatic数,记为$dom(G)$,是$G$的不相交顶点集族的最大可能基数,每个顶点集都是$G$的控制集。众所周知,任何不含孤立点的图都有$dom(G) \geq 2$。对于每一个$k$,已知存在最小度至少为$k$且具有$dom(G)=2$的图。本文证明了如果$G$是$k$ -正则的或{ \em almost} $k$ -正则的(“almost”是指对于某个固定的实数$C \geq 1$,最小度是$k$,最大度至多是$Ck$),则不是这样.在这种情况下,我们证明了$dom(G) \geq (1+o_k(1))k/(2\ln k)$。我们还证明了数量级$k/\ln k$不能提高。不能用小于1的常数代替常数2。证明使用所谓的{ \em半随机方法},这意味着组合对象是通过重复应用概率方法生成的;在我们的情况下,迭代应用Lovász局部引理。

英文摘要:

The domatic number of a graph $G$, denoted $dom(G)$, is the maximum possible cardinality of a family of disjoint sets of vertices of $G$, each set being a dominating set of $G$. It is well known that every graph without isolated vertices has $dom(G) \geq 2$. For every $k$, it is known that there are graphs with minimum degree at least $k$ and with $dom(G)=2$. In this paper we prove that this is not the case if $G$ is $k$-regular or {\em almost} $k$-regular (by ``almost'' we mean that the minimum degree is $k$ and the maximum degree is at most $Ck$ for some fixed real number $C \geq 1$). In this case we prove that $dom(G) \geq (1+o_k(1))k/(2\ln k)$. We also prove that the order of magnitude $k/\ln k$ cannot be improved. One cannot replace the constant 2 with a constant smaller than 1. The proof uses the so called {\em semi-random method} which means that combinatorial objects are generated via repeated applications of the probabilistic method; in our case iterative applications of the Lovász Local Lemma.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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