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arXiv 2104.10055math.NT
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两个新形式的傅里叶系数的除数

Divisors of Fourier coefficients of two newforms

Arvind Kumar, Moni Kumari

AI总结:

本研究在广义黎曼假设下,针对权值至少为2的不同非复乘新形式对,估计了其傅里叶系数差的不同素除数个数满足特定上界的素数集合,并由此得到同余素数个数的上界及新形式的唯一性结果。

摘要:

对于一对权值至少为2、具有有理整傅里叶系数$a_{1}(n)$和$a_{2}(n)$的不同非复乘(non-CM)新形式,在广义黎曼假设(GRH)下,我们得到了满足$$ ω(a_1(p)-a_2(p)) \le [ 7k+{1}/{2}+k^{1/5}]$$的素数$p$集合的估计,其中$ω(n)$表示整数$n$的不同素除数的个数,$k$是它们权值的最大值。作为应用,在GRH下,我们证明了给出两个此类新形式之间同余关系的素数个数以$[7k+{1}/{2}+k^{1/5} ]$为界。我们还通过同余关系得到了新形式的一个唯一性结果。

英文摘要:

For a pair of distinct non-CM newforms of weights at least 2, having rational integral Fourier coefficients $a_{1}(n)$ and $a_{2}(n)$, under GRH, we obtain an estimate for the set of primes $p$ such that $$ ω(a_1(p)-a_2(p)) \le [ 7k+{1}/{2}+k^{1/5}],$$ where $ω(n)$ denotes the number of distinct prime divisors of an integer $n$ and $k$ is the maximum of their weights. As an application, under GRH, we show that the number of primes giving congruences between two such newforms is bounded by $[7k+{1}/{2}+k^{1/5} ]$. We also obtain a multiplicity one result for newforms via congruences.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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