arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 2007.01920math.NT
收藏

随机变量$w_x$与Dirichlet除数问题的关系

Relations between the random variable $w_x$ and the Dirichlet divisor problem

Dmitry S. Pyatin

摘要:

我们已经开发了一个启发式表明,在狄利克雷除数问题的几乎所有$n \in \mathbb{N}^{+}$:$$ R(n) \leq O(ψ(n)n^{\frac{1}{4}}) $$其中$$ R(n) = \Big\lvert \sum_{x=1}^{n}\Big\lfloor\frac{n}{x}\Big\rfloor - n\log{n} - (2γ-1)n \Big\rvert $$和$ ψ(n) $ -任何正函数,增加无限的$ n \to \infty $。该结果是在以下假设下实现的:$$ \Big \{\frac{n}{x} \Big \} \sim w_x $$其中$ w_x $均匀分布在$ [0,1) $随机变量上,具有值集合$ \{0, \frac {1} {x}, \ldots, \frac{x-1}{x} \} $和值接受概率$ p = \frac{1}{x} $。本文最后用一个数字论证支持假设是真的。结果表明,对于所有$n < 10^{5}$,期望值:$$μ_{1} \Big[\sum_{x=1}^{n}\Big(\frac{n}{x} - \frac{x-1}{2x}\Big) \Big]= (2n+1)H_{\lfloor\sqrt{n}\rfloor} - \lfloor\sqrt{n}\rfloor^{2} - \lfloor\sqrt{n}\rfloor + C$$与$D(n)$的偏差绝对值小于$R(n)$。

英文摘要:

We have developed a heuristic showing that in the Dirichlet divisor problem for the almost all $n \in \mathbb{N}^{+}$: $$ R(n) \leq O(ψ(n)n^{\frac{1}{4}}) $$ where $$ R(n) = \Big\lvert \sum_{x=1}^{n}\Big\lfloor\frac{n}{x}\Big\rfloor - n\log{n} - (2γ-1)n \Big\rvert $$ and $ ψ(n) $ - any positive function that increases unboundedly as $ n \to \infty $. The result is achieved under the hypothesis: $$ \Big \{\frac{n}{x} \Big \} \sim w_x $$ where $ w_x $ is uniformly distributed over $ [0,1) $ random variable with a values set $ \{0, \frac {1} {x}, \ldots, \frac{x-1}{x} \} $ and the value accepting probability $ p = \frac{1}{x} $. The paper concludes with a numerical argument in support of the hypothesis being true. It is shown that the expectation: $$μ_{1} \Big[\sum_{x=1}^{n}\Big(\frac{n}{x} - \frac{x-1}{2x}\Big) \Big]= (2n+1)H_{\lfloor\sqrt{n}\rfloor} - \lfloor\sqrt{n}\rfloor^{2} - \lfloor\sqrt{n}\rfloor + C$$ has deviation from $D(n)$ is less than $R(n)$ in absolute value for all $n < 10^{5}$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑