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arXiv 1102.4542math.FA
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绝对和多重线性算子的余型与Grothendieck型定理

On cotype and a Grothendieck-type theorem for absolutely summing multilinear operators

A. Thiago Lopes Bernardino

摘要:

Grothendieck的一个著名的结果断言,从$\ell_{1}$到$\ell_{2}$的每一个连续线性算子绝对是$(1,1)$ -求和的.如果$n\geq2,$然而,这是非常简单的证明,每一个连续的$n$ -线性算子从$\ell_{1}\times...\times\ell_{1}$到$\ell_{2}$是绝对$(1;1,...,1) $ -求和,甚至绝对$(\frac{2}% {n};1,...,1) $ -求和$.$在这篇文章中,我们处理以下问题:给定一个正整数$n\geq2$,什么是最好的常数$g_{n}>0$,使每一个$n$ -线性算子从$\ell_{1}\times...\times\ell_{1}$到$\ell_{2}$是绝对$(g_{n};1,...,1) $ -求和?我们证明了$g_{n}\leq\frac{2}{n+1}$,并获得了最佳的改进以前最近的结果(由于亨氏Juenk $\mathit{et}$ $\mathit{al}$,杰拉尔多Botelho $\mathit{et}$ $\mathit{al}$和杜米特鲁波帕)包含定理绝对求和多重线性算子。

英文摘要:

A famous result due to Grothendieck asserts that every continuous linear operator from $\ell_{1}$ to $\ell_{2}$ is absolutely $(1,1)$-summing. If $n\geq2,$ however, it is very simple to prove that every continuous $n$-linear operator from $\ell_{1}\times...\times\ell_{1}$ to $\ell_{2}$ is absolutely $(1;1,...,1) $-summing, and even absolutely $(\frac{2}% {n};1,...,1) $-summing$.$ In this note we deal with the following problem: Given a positive integer $n\geq2$, what is the best constant $g_{n}>0$ so that every $n$-linear operator from $\ell_{1}\times...\times\ell_{1}$ to $\ell_{2}$ is absolutely $(g_{n};1,...,1) $-summing? We prove that $g_{n}\leq\frac{2}{n+1}$ and also obtain an optimal improvement of previous recent results (due to Heinz Juenk $\mathit{et}$ $\mathit{al}$, Geraldo Botelho $\mathit{et}$ $\mathit{al}$ and Dumitru Popa) on inclusion theorems for absolutely summing multilinear operators.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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