arXivDaily arXiv每日学术速递 周一至周五更新
arXiv周末暂无论文更新,休息一下吧,周末愉快~~
arXiv 0905.4049math.SGmath.AT
收藏

具有极小不动集的Hamilton圈作用

Hamiltonian circle actions with minimal fixed sets

Hui Li, Susan Tolman

摘要:

考虑紧致辛$2n$维流形$(M, ω)$上的有效Hamilton圈作用.假设固定集合$M^{S^1}$是{ \em minimal},在两种意义上:它正好有两个分量,$X$和$Y$,以及$\dim(X) + \dim(Y) = \dim(M) - 2$。本文证明了$M$的整上同调环和Chern类同构于$\CP^n$的整上同调环和Chern类,或者同构于$\R^{n+2}$中定向二平面的Grassmannian算子$\Gt_2(\R^{n+2})$的整上同调环和Chern类(如果$n \neq 1$是奇数).特别地,所有$i$的$H^i(M;\Z) = H^i(\CP^n;\Z)$和$M$的Chern类由积分上同调{ \em环}确定。我们还证明了$M$的固定集数据完全符合固定集数据的标准圆行动之一,这两个流形。特别是,我们表明,有没有点与稳定剂$\Z_k$的任何$k > 2$。当$M^{S^1}$恰好有两个分量并且$M$的偶数Betti数最小时,即对于所有$i \in \{0,...,1/2\dim(M)\}$都是$b_{2i}(M) = 1$时,同样的结论也成立。这提供了额外的证据,很少有辛流形的最小甚至贝蒂数承认汉密尔顿行动。

英文摘要:

Consider an effective Hamiltonian circle action on a compact symplectic $2n$-dimensional manifold $(M, ω)$. Assume that the fixed set $M^{S^1}$ is {\em minimal}, in two senses: it has exactly two components, $X$ and $Y$, and $\dim(X) + \dim(Y) = \dim(M) - 2$. We prove that the integral cohomology ring and Chern classes of $M$ are isomorphic to either those of $\CP^n$ or (if $n \neq 1$ is odd) to those of $\Gt_2(\R^{n+2})$, the Grassmannian of oriented two-planes in $\R^{n+2}$. In particular, $H^i(M;\Z) = H^i(\CP^n;\Z)$ for all $i$, and the Chern classes of $M$ are determined by the integral cohomology {\em ring}. We also prove that the fixed set data of $M$ agrees exactly with the fixed set data for one of the standard circle actions on one of these two manifolds. In particular, we show that there are no points with stabilizer $\Z_k$ for any $k > 2$. The same conclusions hold when $M^{S^1}$ has exactly two components and the even Betti numbers of $M$ are minimal, that is, $b_{2i}(M) = 1$ for all $i \in \{0,...,1/2\dim(M)\}$. This provides additional evidence that very few symplectic manifolds with minimal even Betti numbers admit Hamiltonian actions.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑