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arXiv 2201.06846math.COcs.ITmath.IT
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长度为5和6的三种码的最大基数

The maximum cardinality of trifferent codes with lengths 5 and 6

Stefano Della Fiore, Alessandro Gnutti, Sven Polak

摘要:

当对于$\mathcal{C}$的任何三个不同的元素存在它们都不同的坐标时,代码$\mathcal{C} \subseteq \{0, 1, 2\}^n$被称为与长度$n$三异。将$\mathcal{T}(n)$定义为长度为$n$的三个不同码的最大基数,对于$n \ge 5$,$\mathcal{T}(n)$是未知的。在本文中,我们使用一个优化的搜索算法来证明$\mathcal{T}(5) = 10$和$\mathcal{T}(6) = 13$。

英文摘要:

A code $\mathcal{C} \subseteq \{0, 1, 2\}^n$ is said to be trifferent with length $n$ when for any three distinct elements of $\mathcal{C}$ there exists a coordinate in which they all differ. Defining $\mathcal{T}(n)$ as the maximum cardinality of trifferent codes with length $n$, $\mathcal{T}(n)$ is unknown for $n \ge 5$. In this note, we use an optimized search algorithm to show that $\mathcal{T}(5) = 10$ and $\mathcal{T}(6) = 13$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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