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arXiv 2004.02145math.FAmath.OA
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多重算子积分和广义绝对值函数的弱$(1,1)$估计

Weak $(1,1)$ estimates for multiple operator integrals and generalized absolute value functions

Martijn Caspers, Fedor Sukochev, Dmitriy Zanin

摘要:

考虑由\[ a(t) = \vert t \vert t^{n-1}, \qquad t \in \mathbb{R}, n \in \mathbb{N}_{\geq 1}. \]定义的广义绝对值函数。此外,考虑$n$阶除差函数$a^{[n]}: \mathbb{R}^{n+1} \rightarrow \mathbb{C}$,并设$1 < p_1, \ldots, p_n < \infty$使得$\sum_{l=1}^n p_l^{-1} = 1$。设$\mathcal{S}_{p_l}$表示Schatten-von Neumann理想,$\mathcal{S}_{1,\infty}$表示弱迹类理想.我们证明了对于任何有界自伴算子的$(n+1)$元组${\bf A}$,重算子积分$T_{a^{[n]}}^{\bf A}$将$\mathcal{S}_{p_1} \times \ldots \times \mathcal{S}_{p_n}$有界映射到$\mathcal{S}_{1, \infty}$,且在${\bf A}$中有一致界.对于在区间$[-1, 1]$之外等于$a$的$C^{n+1}$ -函数类也是如此。在[CLPST 16]中,证明了对于这类函数$f$,从$\mathcal{S}_{p_1} \times \ldots \times \mathcal{S}_{p_n}$到$\mathcal{S}_{1}$的$T^{ {\bf A} }_{f^{[n]}}$的有界性可能失败,解决了V. Peller的问题。这表明本文中的估计是最优的。证明是基于一个新的减少方法的任意多个算子积分的分歧。

英文摘要:

Consider the generalized absolute value function defined by \[ a(t) = \vert t \vert t^{n-1}, \qquad t \in \mathbb{R}, n \in \mathbb{N}_{\geq 1}. \] Further, consider the $n$-th order divided difference function $a^{[n]}: \mathbb{R}^{n+1} \rightarrow \mathbb{C}$ and let $1 < p_1, \ldots, p_n < \infty$ be such that $\sum_{l=1}^n p_l^{-1} = 1$. Let $\mathcal{S}_{p_l}$ denote the Schatten-von Neumann ideals and let $\mathcal{S}_{1,\infty}$ denote the weak trace class ideal. We show that for any $(n+1)$-tuple ${\bf A}$ of bounded self-adjoint operators the multiple operator integral $T_{a^{[n]}}^{\bf A}$ maps $\mathcal{S}_{p_1} \times \ldots \times \mathcal{S}_{p_n}$ to $\mathcal{S}_{1, \infty}$ boundedly with uniform bound in ${\bf A}$. The same is true for the class of $C^{n+1}$-functions that outside the interval $[-1, 1]$ equal $a$. In [CLPST16] it was proved that for a function $f$ in this class such boundedness of $T^{ {\bf A} }_{f^{[n]}}$ from $\mathcal{S}_{p_1} \times \ldots \times \mathcal{S}_{p_n}$ to $\mathcal{S}_{1}$ may fail, resolving a problem by V. Peller. This shows that the estimates in the current paper are optimal. The proof is based on a new reduction method for arbitrary multiple operator integrals of divided differences.

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