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arXiv 1707.04542math.GT
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$S^1\times S^2$中结的一致性

Concordance of knots in $S^1\times S^2$

University of Wisconsin–Eau Claire(威斯康星大学欧克莱尔分校);McMaster University(麦克马斯特大学);Max-Planck-Institut für Mathematik(马克斯·普朗克数学研究所)

Christopher W. Davis, Matthias Nagel, JungHwan Park, Arunima Ray

AI总结:

研究$S^1\times S^2$中结的光滑与拓扑一致性,证明风数为1的结有唯一光滑一致性类,揭示光滑与拓扑类别的区别。

摘要:

我们建立了关于$S^1\times S^2$中结的光滑与拓扑一致性的若干结果。定义$S^1\times S^2$中结的环绕数为其在$H_1(S^1\times S^2;\mathbb{Z})\cong \mathbb{Z}$中的类。我们证明风数为1的结有唯一的光滑一致性类,改进了Friedl-Nagel-Orson-Powell在拓扑范畴中的相应结果。我们说$S^1\times S^2$中的结是slice(resp. 拓扑slice)如果它在$D^2\times S^2$中界一个光滑(resp. 局部平坦)盘。我们证明存在无限多个非slice结的拓扑一致性类,并且对于任何非±1的环绕数,存在无限多个slice结的拓扑一致性类。此外,我们通过构造无限族slice结来展示光滑与拓扑类别的区别,这些结在拓扑上但不光滑一致,同时存在非slice结在拓扑上slice且拓扑一致但不光滑一致。

英文摘要:

We establish a number of results about smooth and topological concordance of knots in $S^1\times S^2$. The winding number of a knot in $S^1\times S^2$ is defined to be its class in $H_1(S^1\times S^2;\mathbb{Z})\cong \mathbb{Z}$. We show that there is a unique smooth concordance class of knots with winding number one. This improves the corresponding result of Friedl-Nagel-Orson-Powell in the topological category. We say a knot in $S^1\times S^2$ is slice (resp. topologically slice) if it bounds a smooth (resp. locally flat) disk in $D^2\times S^2$. We show that there are infinitely many topological concordance classes of non-slice knots, and moreover, for any winding number other than $\pm 1$, there are infinitely many topological concordance classes even within the collection of slice knots. Additionally we demonstrate the distinction between the smooth and topological categories by constructing infinite families of slice knots that are topologically but not smoothly concordant, as well as non-slice knots that are topologically slice and topologically concordant, but not smoothly concordant.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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