arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 1702.00828math.CO
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Grundy控制序列与迫零集

Grundy dominating sequences and zero forcing sets

Boštjan Brešar, Csilla Bujtás, Tanja Gologranc, Sandi Klavžar, Gašper Košmrlj, Balázs Patkós, Zsolt Tuza, Máté Vizer

摘要:

在图$G$中,顶点序列$v_1,v_2,\dots,v_m$是Grundy控制的,如果对于所有的$2\le i \le m$,我们有$N[v_i]\not\subseteq \cup_{j=1}^{i-1}N[v_j]$,并且是Grundy全控制的,如果对于所有的$2\le i \le m$,我们有$N(v_i)\not\subseteq \cup_{j=1}^{i-1}N(v_j)$。最长Grundy(全)控制序列的长度已被一些作者研究过。在本文中,我们引入了两个类似的概念时,对邻域的要求改为$N(v_i)\not\subseteq \cup_{j=1}^{i-1}N[v_j]$或$N[v_i]\not\subseteq \cup_{j=1}^{i-1}N(v_j)$。在前一种情况下,我们建立了一个强连接的迫零数的图,而我们确定的复杂性的判定问题在后一种情况下。我们还研究了这四个概念之间的关系,并讨论了它们的计算复杂性。

英文摘要:

In a graph $G$ a sequence $v_1,v_2,\dots,v_m$ of vertices is Grundy dominating if for all $2\le i \le m$ we have $N[v_i]\not\subseteq \cup_{j=1}^{i-1}N[v_j]$ and is Grundy total dominating if for all $2\le i \le m$ we have $N(v_i)\not\subseteq \cup_{j=1}^{i-1}N(v_j)$. The length of the longest Grundy (total) dominating sequence has been studied by several authors. In this paper we introduce two similar concepts when the requirement on the neighborhoods is changed to $N(v_i)\not\subseteq \cup_{j=1}^{i-1}N[v_j]$ or $N[v_i]\not\subseteq \cup_{j=1}^{i-1}N(v_j)$. In the former case we establish a strong connection to the zero forcing number of a graph, while we determine the complexity of the decision problem in the latter case. We also study the relationships among the four concepts, and discuss their computational complexities.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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