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arXiv 0801.3770math.RA
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离散赋值环上的最大叉积序

Maximal Crossed Product Orders over Discrete Valuation Rings

Yuval Ginosar

摘要:

确定离散赋值环$S$上的有限群$G$的(经典)交叉积$T=S^f*G$何时是最大阶的问题,在20世纪60年代回答了$S$在不变量子环$S^G$上的tamely分歧的情况。根据惯性的导体子组(相对于$f$)给出了答案。在本文中,我们解决了这个问题一般情况下,当$S/S^G$是剩余可分的。我们证明了最大阶性质在由惯性子群分次的次交叉积上具有一个限制性结构。特别地,惯性是阿贝尔的。利用这种结构,人们能够扩展导体的概念。与tame情形一样,导体的阶等于$T$的极大双边理想的个数,因此等于其商环中包含$T$的极大阶的个数。因此,$T$是极大阶当且仅当导子群是平凡的。

英文摘要:

The problem of determining when a (classical) crossed product $T=S^f*G$ of a finite group $G$ over a discrete valuation ring $S$ is a maximal order, was answered in the 1960's for the case where $S$ is tamely ramified over the subring of invariants $S^G$. The answer was given in terms of the conductor subgroup (with respect to $f$) of the inertia. In this paper we solve this problem in general when $S/S^G$ is residually separable. We show that the maximal order property entails a restrictive structure on the sub-crossed product graded by the inertia subgroup. In particular, the inertia is abelian. Using this structure, one is able to extend the notion of the conductor. As in the tame case, the order of the conductor is equal to the number of maximal two sided ideals of $T$ and hence to the number of maximal orders containing $T$ in its quotient ring. Consequently, $T$ is a maximal order if and only if the conductor subgroup is trivial.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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