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arXiv math/0502530math.DG
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中曲率流的收敛速率

The rate of convergence of the mean curvature flow

Tom Ilmanen, Natasa Sesum

摘要:

本文利用$\mathrm{R}^{n+1}$中光滑严格凸超曲面的中曲率来研究其流$M_t$。表面保持光滑和凸,单调收缩,直到它消失在一个关键的时间$T$和点$x^*$(这是由于Huisken)。这相当于说相应的重新缩放的中曲率流收敛到半径为$\sqrt{n}$的球体${\bf S^n}$。本文主要研究重标流的指数收敛速度。我们将在这里提出一种方法,告诉我们的指数衰减率至少是$\frac{2}{n}$。当一个光滑的严格凸的$n$维超曲面以等于其中曲率的法向速度运动时,我们可以定义它的“到达时间”$u$为$u(x) = t$,如果$x\in M_t$为$x\in \Int(M_0)$。Huisken证明了对于$n\ge 2$,$u(x)$是$C^2$接近$x^*$。Kohn和Serfaty对$n=1$病例进行了处理,证明了$u$的$C^3$规律性。作为一个结果,获得的收敛速率的中曲率流,我们证明了$u$不是$C^3$附近的$x^*$为$n\ge 2$。我们还表明,所获得的收敛速率$2/n$,从线性化的中曲率流是最佳的,至少对于$n\ge 2$。

英文摘要:

We study the flow $M_t$ of a smooth, strictly convex hypersurface by its mean curvature in $\mathrm{R}^{n+1}$. The surface remains smooth and convex, shrinking monotonically until it disappears at a critical time $T$ and point $x^*$ (which is due to Huisken). This is equivalent to saying that the corresponding rescaled mean curvature flow converges to a sphere ${\bf S^n}$ of radius $\sqrt{n}$. In this paper we will study the rate of exponential convergence of a rescaled flow. We will present here a method that tells us the rate of the exponential decay is at least $\frac{2}{n}$. We can define the ''arrival time'' $u$ of a smooth, strictly convex $n$-dimensional hypersurface as it moves with normal velocity equal to its mean curvature as $u(x) = t$, if $x\in M_t$ for $x\in \Int(M_0)$. Huisken proved that for $n\ge 2$ $u(x)$ is $C^2$ near $x^*$. The case $n=1$ has been treated by Kohn and Serfaty, they proved $C^3$ regularity of $u$. As a consequence of obtained rate of convergence of the mean curvature flow we prove that $u$ is not $C^3$ near $x^*$ for $n\ge 2$. We also show that the obtained rate of convergence $2/n$, that comes out from linearizing a mean curvature flow is the optimal one, at least for $n\ge 2$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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