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arXiv 2203.02537math.GR
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所有元素都不属于具有素数幂阶的正规子群的群

Groups having all elements off a normal subgroup with prime power order

Mark L. Lewis

摘要:

考虑有限群$G$具有一个正规子群$N$,使得$G \setminus N$的所有元素都有素数幂阶.证明了若存在一个素数$p$,使得$G \setminus N$中的所有元素都有$p$ -幂序,则$G$是$p$ -群或$G = PN$,其中$P$是Sylow $p$ -子群,$(G,P,P \cap N)$是Frobenius-Wielandt三元组.证明了如果$G \setminus N$的所有元素都有素数幂阶,且这些阶能被两个素数$p$和$q$整除,则$G$是$\{ p, q \}$ -群,而$G/N$是Frobenius群或$2$-Frobenius群.如果$G \setminus N$的所有元素都有素数幂阶,并且这些阶至少能被三个素数整除,则$G$的所有元素都有素数幂阶,并且$G/N$是不可解的。

英文摘要:

We consider a finite group $G$ with a normal subgroup $N$ so that all elements of $G \setminus N$ have prime power order. We prove that if there is a prime $p$ so that all the elements in $G \setminus N$ have $p$-power order, then either $G$ is a $p$-group or $G = PN$ where $P$ is a Sylow $p$-subgroup and $(G,P,P \cap N)$ is a Frobenius-Wielandt triple. We also prove that if all the elements of $G \setminus N$ have prime power orders and the orders are divisible by two primes $p$ and $q$, then $G$ is a $\{ p, q \}$-group and $G/N$ is either a Frobenius group or a $2$-Frobenius group. If all the elements of $G \setminus N$ have prime power orders and the orders are divisible by at least three primes, then all elements of $G$ have prime power order and $G/N$ is nonsolvable.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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