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arXiv 2012.06393math.PRcs.NAmath.NA
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正随机矩阵的缩放:集中性与渐近收敛

Scaling positive random matrices: concentration and asymptotic convergence

Boris Landa

AI总结:

本文研究随机正矩阵缩放的集中性与渐近收敛性,针对元素满足一定独立性的随机矩阵,建立了缩放因子及缩放后矩阵在算子范数下的集中不等式,并在双随机缩放情形下得到高概率的 $\mathcal{O}(\sqrt{\log N / N})$ 收敛界。

摘要:

众所周知,任何正矩阵都可以通过将其行和列乘以某些正缩放因子(在相差一个正标量的意义下唯一)来缩放为具有指定行和与列和。这一过程被称为矩阵缩放,并已在运筹学、经济学、图像处理和机器学习中得到广泛应用。在本工作中,我们研究当待缩放矩阵是随机矩阵时,缩放因子以及所得缩放后矩阵的行为。具体而言,令 $\widetilde{A}\in\mathbb{R}^{M\times N}$ 为一个正且有界的随机矩阵,其元素满足某种类型的独立性,我们给出了 $\widetilde{A}$ 的缩放因子围绕 $A = \mathbb{E}[\widetilde{A}]$ 的缩放因子的集中不等式。该结果被用于界定 $\widetilde{A}$ 的缩放因子向 $A$ 的缩放因子收敛的速率,以及在 $M,N\rightarrow\infty$ 时 $\widetilde{A}$ 的缩放版本在算子范数下围绕 $A$ 的缩放版本的集中性。当 $\widetilde{A}$ 的元素相互独立、$M=N$,且所有指定的行和与列和均为 $1$(即双随机矩阵缩放)时,前述两个界均以高概率为 $\mathcal{O}(\sqrt{\log N / N})$。我们在若干模拟中展示了这些结果。

英文摘要:

It is well known that any positive matrix can be scaled to have prescribed row and column sums by multiplying its rows and columns by certain positive scaling factors (which are unique up to a positive scalar). This procedure is known as matrix scaling, and has found numerous applications in operations research, economics, image processing, and machine learning. In this work, we investigate the behavior of the scaling factors and the resulting scaled matrix when the matrix to be scaled is random. Specifically, letting $\widetilde{A}\in\mathbb{R}^{M\times N}$ be a positive and bounded random matrix whose entries assume a certain type of independence, we provide a concentration inequality for the scaling factors of $\widetilde{A}$ around those of $A = \mathbb{E}[\widetilde{A}]$. This result is employed to bound the convergence rate of the scaling factors of $\widetilde{A}$ to those of $A$, as well as the concentration of the scaled version of $\widetilde{A}$ around the scaled version of $A$ in operator norm, as $M,N\rightarrow\infty$. When the entries of $\widetilde{A}$ are independent, $M=N$, and all prescribed row and column sums are $1$ (i.e., doubly-stochastic matrix scaling), both of the previously-mentioned bounds are $\mathcal{O}(\sqrt{\log N / N})$ with high probability. We demonstrate our results in several simulations.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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