arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 2004.13126math.CO
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路径图$P_2$与$P_n$的笛卡尔积的Maker-Breaker控制数

Maker-Breaker domination number for Cartesian products of path graphs $P_2$ and $P_n$

Jovana Forcan, Jiayue Qi

AI总结:

该研究针对图上的Maker-Breaker控制博弈,推导了任意图及两顶点完全图与任意图笛卡尔积的控制数上界,精准确定了路径图P₂与Pₙ的笛卡尔积及其不交并的先手、后手Maker-Breaker控制数的精确值。

摘要:

我们研究由Dominator(控制者)和Staller(阻碍者)在给定图的顶点集上进行的Maker-Breaker控制博弈。当控制者声称的顶点构成图的一个控制集时,控制者获胜;若阻碍者使得控制者无法获胜,即阻碍者能够声称某个顶点及其所有邻点,则阻碍者获胜。图$G$的Maker-Breaker控制数$\gamma_{MB}(G)$($\gamma'_{MB}(G)$)定义为控制者先手(后手)时保证自己获胜所需的最少步数。我们研究了任意图的笛卡尔积的这两个不变量,得到了任意图笛卡尔积的Maker-Breaker控制数的上界,还给出了两顶点完全图与任意图的笛卡尔积的Maker-Breaker控制数上界。最重要的是,我们证明了当$n\geq1$时$\gamma'_{MB}(P_2\square P_n)=n$;$\gamma_{MB}(P_2\square P_n)$在$1\leq n\leq4$、$5\leq n\leq12$、$n\geq13$时分别等于$n$、$n-1$、$n-2$。对于$P_2\square P_n$的不交并,我们证明$\gamma_{MB}'(\dot\cup_{i=1}^k(P_2\square P_n)_i)=k\cdot n$($n\geq1$),且$\gamma_{MB}(\dot\cup_{i=1}^k(P_2\square P_n)_i)$在$1\leq n\leq4$、$5\leq n\leq12$、$n\geq13$时分别等于$k\cdot n$、$k\cdot n-1$、$k\cdot n-2$。

英文摘要:

We study the Maker-Breaker domination game played by Dominator and Staller on the vertex set of a given graph. Dominator wins when the vertices he has claimed form a dominating set of the graph. Staller wins if she makes it impossible for Dominator to win, or equivalently, she is able to claim some vertex and all its neighbours. Maker-Breaker domination number $γ_{MB}(G)$ ($γ'_{MB}(G)$) of a graph $G$ is defined to be the minimum number of moves for Dominator to guarantee his winning when he plays first (second). We investigate these two invariants for the Cartesian product of any two graphs. We obtain upper bounds for the Maker-Breaker domination number of the Cartesian product of two arbitrary graphs. Also, we give upper bounds for the Maker-Breaker domination number of the Cartesian product of the complete graph with two vertices and an arbitrary graph. Most importantly, we prove that $γ'_{MB}(P_2\square P_n)=n$ for $n\geq 1$, $γ_{MB}(P_2\square P_n)$ equals $n$, $n-1$, $n-2$, for $1\leq n\leq 4$, $5\leq n\leq 12$, and $n\geq 13$, respectively. For the disjoint union of $P_2\square P_n$s, we show that $γ_{MB}'(\dot\cup_{i=1}^k(P_2\square P_n)_i)=k\cdot n$ ($n\geq 1$), and that $γ_{MB}(\dot\cup_{i=1}^k(P_2\square P_n)_i)$ equals $k\cdot n$, $k\cdot n-1$, $k\cdot n-2$ for $1\leq n\leq 4$, $5\leq n\leq 12$, and $n\geq 13$, respectively.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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