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arXiv 2003.00623math.GT

双扭结的左序手术 II

Left orderable surgeries of double twist knots II

Vu The Khoi, Masakazu Teragaito, Anh T. Tran

AI总结:

本文完善了双桥纽结左序斜率存在性的证明,利用双曲SL₂(ℝ)表示的连续族,证明C(2m+1,-2n)在区间(-4n,4m)内所有斜率均为左序斜率。

摘要:

若沿纽结 $K \subset S^3$ 进行 $r$-手术得到的 3-流形具有左序基本群,则斜率 $r$ 被称为纽结 $K$ 的左序斜率。考虑 Conway 记号中的双桥纽结 $C(2m, \pm 2n)$ 和 $C(2m+1, -2n)$,其中 $m \ge 1$ 和 $n \ge 2$ 为整数。通过使用纽结群的双曲 $\mathrm{SL}_2(\mathbb{R})$-表示的连续族,在文献 \cite{HT-genus1, Tr} 中证明了 $(-4n, 4m)$(分别为 $[0, \max\{4m, 4n\})$)中的任何斜率是 $C(2m, 2n)$(分别为 $C(2m, -2n)$)的左序斜率,在文献 \cite{Ga} 中证明了 $(-4n,0]$ 中的任何斜率是 $C(2m+1,-2n)$ 的左序斜率。然而,这些结果的证明并不完整,因为表示的族的连续性未被证明。在本文中,我们完善了这些证明,并且进一步证明了 $(-4n, 4m)$ 中的任何斜率都是 $C(2m+1,-2n)$ 的左序斜率,该斜率由纽结群的双曲 $\mathrm{SL}_2(\mathbb{R})$-表示所检测。

英文摘要:

A slope $r$ is called a left orderable slope of a knot $K \subset S^3$ if the 3-manifold obtained by $r$-surgery along $K$ has left orderable fundamental group. Consider two-bridge knots $C(2m, \pm 2n)$ and $C(2m+1, -2n)$ in the Conway notation, where $m \ge 1$ and $n \ge 2$ are integers. By using \textit{continuous} families of hyperbolic $\mathrm{SL}_2(\mathbb{R})$-representations of knot groups, it was shown in \cite{HT-genus1, Tr} that any slope in $(-4n, 4m)$ (resp. $[0, \max\{4m, 4n\})$) is a left orderable slope of $C(2m, 2n)$ (resp. $C(2m, - 2n)$) and in \cite{Ga} that any slope in $(-4n,0]$ is a left orderable slope of $C(2m+1,-2n)$. However, the proofs of these results are incomplete since the \textit{continuity} of the families of representations was not proved. In this paper, we complete these proofs and moreover we show that any slope in $(-4n, 4m)$ is a left orderable slope of $C(2m+1,-2n)$ detected by hyperbolic $\mathrm{SL}_2(\mathbb{R})$-representations of the knot group.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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