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arXiv 1805.04744math.DS
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β-展开式上的丢番图逼近和游程函数

Diophantine approximation and run-length function on β-expansions

Lixuan Zheng

摘要:

对于任何$β> 1$,用$r_n(x,β)$表示,是$x\in[0,1]$的$β$扩展的第一个$n$数字中连续零的最大长度。$\frac{r_n(x,β)}{n}$的上极限(分别为下极限)与经典的丢番图逼近(分别为均匀的丢番图逼近)有关。我们得到了水平集$$E_{a,b}=\left\{x \in [0,1]: \liminf_{n\rightarrow \infty}\frac{r_n(x,β)}{n}=a,\ \limsup_{n\rightarrow \infty}\frac{r_n(x,β)}{n}=b\right\}\ (0\leq a\leq b\leq1).$$的Hausdorff维数.此外,我们还证明了具有零豪斯多夫维数的极发散集$E_{0,1}$是剩余集.同样的问题,在参数空间也进行了检查。

英文摘要:

For any $β> 1$, denoted by $r_n(x,β)$ the maximal length of consecutive zeros amongst the first $n$ digits of the $β$-expansion of $x\in[0,1]$. The limit superior (respectively limit inferior) of $\frac{r_n(x,β)}{n}$ is linked to the classical Diophantine approximation (respectively uniform Diophantine approximation). We obtain the Hausdorff dimension of the level set $$E_{a,b}=\left\{x \in [0,1]: \liminf_{n\rightarrow \infty}\frac{r_n(x,β)}{n}=a,\ \limsup_{n\rightarrow \infty}\frac{r_n(x,β)}{n}=b\right\}\ (0\leq a\leq b\leq1).$$ Furthermore, we show that the extremely divergent set $E_{0,1}$ which is of zero Hausdorff dimension is, however, residual. The same problems in the parameter space are also examined.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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