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arXiv 1508.04484math.CO
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关于精确$k$-Nim的Sprague-Grundy函数

On the Sprague-Grundy function of Exact $k$-Nim

Endre Boros, Vladimir Gurvich, Nhan Bao Ho, Kazuhisa Makino, Peter Mursic

摘要:

摩尔对{\sc Nim}游戏的推广如下。令$n$和$k$是两个整数,使得$1 \leq k \leq n$。给定$n$堆代币,两个玩家交替移动,从至少一个且至多$k$堆中移除代币。走到最后一步的玩家获胜。Moore在1910年解决了这个博弈,Jenkyns和Mayberry在1980年给出了一个Sprague-Grundy函数的显式公式,但仅适用于$n = k+1$。我们引入{\sc Nim}的另一个推广,称为{\sc精确$k$-Nim},其中每次移动都精确地减少$k$堆。在$2k \geq n$情形下,我们给出了{\sc Exact $k$-Nim}的Sprague-Grundy函数的一个显式公式.在$n=2k$的情况下,我们的公式与Jenkyns和Mayberry的公式惊人地相似。

英文摘要:

Moore's generalization of the game of {\sc Nim} is played as follows. Let $n$ and $k$ be two integers such that $1 \leq k \leq n$. Given $n$ piles of tokens, two players move alternately, removing tokens from at least one and at most $k$ of the piles. The player who makes the last move wins. The game was solved by Moore in 1910 and an explicit formula for its Sprague-Grundy function was given by Jenkyns and Mayberry in 1980, for the case $n = k+1$ only. We introduce another generalization of {\sc Nim}, called {\sc Exact $k$-Nim}, in which each move reduces exactly $k$ piles. We give an explicit formula for the Sprague-Grundy function of {\sc Exact $k$-Nim} in case $2k \geq n$. In case $n=2k$ our formula is surprisingly similar to Jenkyns and Mayberry's one.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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