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arXiv 1407.2844cs.DS
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Steiner循环图-TSP

Graph-TSP from Steiner Cycles

Satoru Iwata, Alantha Newman, R. Ravi

摘要:

提出了一种基于Steiner圈的图度量旅行商问题的求解方法。斯坦纳圈是一个需要包含一些指定的顶点子集的圈。对于一个图$G$,如果我们能找到一个生成树$T$和一个包含$T$中奇度顶点的简单圈,那么我们给出了如何将经典的“双生成树”算法与Christofides算法相结合,得到一个长度至多为$\frac{4n}{3}$的TSP之旅.我们使用这种方法表明,一个图包含一个哈密尔顿路径有一个TSP旅游的长度最多$4n/3$。由于哈密尔顿路径是一个有两片叶子的生成树,这就引出了一个问题:一个包含很少叶子的生成树的图是否有一个短的TSP之旅。Mömke和Svensson最近的技术意味着一个包含$k$叶子的深度优先搜索树的图有一个长度为$4n/3 + O(k)$的TSP之旅。使用我们的方法,我们可以证明,一个$2(k-1)$ -顶点连通图,包含一个生成树,最多$k$叶有一个TSP旅游的长度$4n/3$。我们还探讨了其他条件下,我们的方法在短期内的结果。

英文摘要:

We present an approach for the traveling salesman problem with graph metric based on Steiner cycles. A Steiner cycle is a cycle that is required to contain some specified subset of vertices. For a graph $G$, if we can find a spanning tree $T$ and a simple cycle that contains the vertices with odd-degree in $T$, then we show how to combine the classic "double spanning tree" algorithm with Christofides' algorithm to obtain a TSP tour of length at most $\frac{4n}{3}$. We use this approach to show that a graph containing a Hamiltonian path has a TSP tour of length at most $4n/3$. Since a Hamiltonian path is a spanning tree with two leaves, this motivates the question of whether or not a graph containing a spanning tree with few leaves has a short TSP tour. The recent techniques of Mömke and Svensson imply that a graph containing a depth-first-search tree with $k$ leaves has a TSP tour of length $4n/3 + O(k)$. Using our approach, we can show that a $2(k-1)$-vertex connected graph that contains a spanning tree with at most $k$ leaves has a TSP tour of length $4n/3$. We also explore other conditions under which our approach results in a short tour.

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