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arXiv 1102.4427math.GRmath.RT
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李型单例外群由它们的character度决定

Simple exceptional groups of Lie type are determined by their character degrees

Hung P. Tong-Viet

摘要:

设$G$是有限群.用$\textrm{Irr}(G)$表示$G.$的所有不可约复特征标的集合设$\textrm{cd}(G)=\{χ(1)\;|\;χ\in \textrm{Irr}(G)\}$是$G$的所有不可约复特征标度的集合,且令$\textrm{X}_1(G)$是$G$的所有不可约复特征标度的集合,且计数重数。设$H$是任意非交换的李型单例外群.本文证明了:如果$S$是一个非交换单群,且$\textrm{cd}(S)\subseteq \textrm{cd}(H)$,则$S$必同构于$H.$.由此,我们证明了:如果$G$是一个具有$\textrm{X}_1(G)\subseteq \textrm{X}_1(H)$的有限群,则$G$同构于$H.$.

英文摘要:

Let $G$ be a finite group. Denote by $\textrm{Irr}(G)$ the set of all irreducible complex characters of $G.$ Let $\textrm{cd}(G)=\{χ(1)\;|\;χ\in \textrm{Irr}(G)\}$ be the set of all irreducible complex character degrees of $G$ forgetting multiplicities, and let $\textrm{X}_1(G)$ be the set of all irreducible complex character degrees of $G$ counting multiplicities. Let $H$ be any non-abelian simple exceptional group of Lie type. In this paper, we will show that if $S$ is a non-abelian simple group and $\textrm{cd}(S)\subseteq \textrm{cd}(H)$ then $S$ must be isomorphic to $H.$ As a consequence, we show that if $G$ is a finite group with $\textrm{X}_1(G)\subseteq \textrm{X}_1(H)$ then $G$ is isomorphic to $H.$ In particular, this implies that the simple exceptional groups of Lie type are uniquely determined by the structure of their complex group algebras.

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