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arXiv 1010.2601math.NT
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整数的$x^3+y^3+2z^3$基元表示

Primitive Representations of Integers by $x^3+y^3+2z^3$

Samir Siksek

摘要:

一个著名的公开问题是证明三次形式$x^3+y^3+2z^3$表示所有整数。这个问题的一个明显的变体是是否每个整数都可以由\em表示。换句话说,给定一个整数$n$,是否存在互质整数$x$,$y$,$z$使得$x^3+y^3+2z^3=n$?在本说明中,我们否定地回答这个不同的问题。实际上,我们使用三次互易性来表明,对于$x^3+y^3+2z^3=8^m$的每一个整数解,未知数$x$、$y$、$z$都可以被$2^m$整除。

英文摘要:

A well-known open problem is to show that the cubic form $x^3+y^3+2z^3$ represents all integers. An obvious variant of this problem is whether every integer can be {\em primitively} represented by $x^3+y^3+2z^3$. In other words, given an integer $n$, are there coprime integers $x$, $y$, $z$ such that $x^3+y^3+2z^3=n$? In this note we answer this variant question negatively. Indeed, we use cubic reciprocity to show that for every integral solution to $x^3+y^3+2z^3=8^m$,the unknowns $x$, $y$, $z$ are divisible by $2^m$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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