arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 1006.1963nucl-th
收藏

用复标度法计算~ 8He的五体共振

Five-body resonances of 8He using the complex scaling method

Takayuki Myo, Ryosuke Ando, Kiyoshi Kato

摘要:

在4 He +n+n + n + n+n五体团簇模型中研究了~ 8He的0+态.在正确的边界条件下,用复标度法将多体共振作为伽莫夫态处理。在激发能为6.3 MeV,宽度为3.2 MeV的条件下,8 He的0+ 2态为五体共振,主要为(p_{3/2})^2(p_{1/2})^2组态.在该状态下,0+神经元对的数量几乎为2,这与具有大量2+对分量的基态不同。计算了~ 8He从基态到五体非束缚态的跃迁。结果表明,7 He +n分量对强度的消耗最大,而0+ 2分量的贡献可以忽略不计。最后的态是6 He +n+n,而不是4 He +n+n+n+n。结果表明,在双激发下,8He → 7 He +n → 6 He +n+n的连续破碎过程。

英文摘要:

The 0+ states of 8He are studied in a five-body 4He+n+n+n+n cluster model. Many-body resonances are treated on the correct boundary condition as Gamow states using the complex scaling method. The 0+_2 state of 8He is predicted as a five-body resonance in the excitation energy of 6.3 MeV with a width of 3.2 MeV, which mainly has a (p_{3/2})^2(p_{1/2})^2 configuration. In this state, number of the 0+ neuron pair shows almost two, which is different from the ground state having a large amount of the 2+ pair component. The monopole transition of 8He from the ground state into the five-body unbound states is also evaluated. It is found that the 7He+n component mostly exhausts the strength, while the 0+_2 contribution is negligible. The final states are dominated by 6He+n+n, not 4He+n+n+n+n. The results indicate the sequential breakup process of 8He to 7He+n to 6He+n+n by the monopole excitation.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑