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arXiv 1004.4849math.NT
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整数分拆的初等公式

Elementary formulas for integer partitions

Mohamed El Bachraoui

摘要:

本文给出了整数分拆上函数的各种精确公式,包括函数$p(n)$和$p(n,k)$,分别表示$n$的分拆数和分拆成精确$k$部分的分拆数.例如,我们将证明$$ p(n) = \sum_{d|n} \sum_{k=1}^{d} \sum_{i_0 =1}^{\lfloor d/k \rfloor} \sum_{i_1 =i_0}^{\lfloor\frac{d- i_0}{k-1} \rfloor} \sum_{i_2 =i_1}^{\lfloor\frac{d- i_0 - i_1}{k-2} \rfloor} ... \sum_{i_{k-3}=i_{k-4}}^{\lfloor\frac{n- i_0 - i_1-i_2- ...-i_{k-4}}{3} \rfloor} \sum_{c|(d,i_0,i_1,i_2,...,i_{k-3})} μ(c) (\lfloor \frac{d-i_0-i_1-i_2- ... i_{k-3}}{2c} \rfloor - \lfloor\frac{i_{k-3}-1}{c} \rfloor).$$我们的证明是基本的。

英文摘要:

In this note we will give various exact formulas for functions on integer partitions including the functions $p(n)$ and $p(n,k)$ of the number of partitions of $n$ and the number of such partitions into exactly $k$ parts respectively. For instance, we shall prove that $$ p(n) = \sum_{d|n} \sum_{k=1}^{d} \sum_{i_0 =1}^{\lfloor d/k \rfloor} \sum_{i_1 =i_0}^{\lfloor\frac{d- i_0}{k-1} \rfloor} \sum_{i_2 =i_1}^{\lfloor\frac{d- i_0 - i_1}{k-2} \rfloor} ... \sum_{i_{k-3}=i_{k-4}}^{\lfloor\frac{n- i_0 - i_1-i_2- ...-i_{k-4}}{3} \rfloor} \sum_{c|(d,i_0,i_1,i_2,...,i_{k-3})} μ(c) (\lfloor \frac{d-i_0-i_1-i_2- ... i_{k-3}}{2c} \rfloor - \lfloor\frac{i_{k-3}-1}{c} \rfloor).$$ Our proofs are elementary.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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