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arXiv math/9601218math.LOmath.GN
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关于Monk的问题

On Monk's questions

Saharon Shelah

摘要:

蒙克问(问题13,15在他的清单; π是代数密度):“对于一个布尔代数B,aleph_0 <= theta <= pi(B),B是否有一个子代数B',其中pi(B')= theta?如果θ是正则的,那么答案很容易是正的,我们证明,一般来说,它可能是负的,但对于相当多的奇异基数,它是正的;定理是相当互补的。其次,我们处理的pi-chi和我们表明,pi-chi的超积的布尔代数不一定是超积的pi-chi的。证明了对无限布尔代数A_i(i< kappa)和kappa上的非主超滤子D:如果n_i< aleph_0(i< kappa)且mu = prod_{i< kappa} n_i/D是正则的,则pi-chi(A)>= mu.这里A= prod_{i< kappa} A_i/D。根据Peterson的一个定理,需要mu的正则性。

英文摘要:

Monk asks (problems 13, 15 in his list; pi is the algebraic density):''For a Boolean algebra B, aleph_0 <= theta <= pi (B), does B have a subalgebra B' with pi (B')= theta ?'' If theta is regular the answer is easily positive, we show that in general it may be negative, but for quite many singular cardinals - it is positive; the theorems are quite complementary. Next we deal with pi-chi and we show that the pi-chi of an ultraproduct of Boolean algebras is not necessarily the ultraproduct of the pi-chi 's. We also prove that for infinite Boolean algebras A_i (i< kappa) and a non-principal ultrafilter D on kappa : if n_i< aleph_0 for i< kappa and mu = prod_{i< kappa} n_i/D is regular, then pi-chi(A) >= mu. Here A= prod_{i< kappa}A_i/D. By a theorem of Peterson the regularity of mu is needed.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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