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arXiv math/0401300math.CO
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数$6(2n)! /n! (n+2)!$的组合解释

A Combinatorial Interpretation of The Numbers $6(2n)! /n! (n+2)!$

Ira M. Gessel, Guoce Xin

摘要:

众所周知,数字$(2m)! (2n)!/m! n! (m+n)!$是整数,但通常没有已知的组合解释。当$m=0$时,这些数字是中间二项式系数$\binom{2n}{n}$,当$m=1$时,它们是加泰罗尼亚数字的两倍。本文给出了当$m=2$或3.

英文摘要:

It is well known that the numbers $(2m)! (2n)!/m! n! (m+n)!$ are integers, but in general there is no known combinatorial interpretation for them. When $m=0$ these numbers are the middle binomial coefficients $\binom{2n}{n}$, and when $m=1$ they are twice the Catalan numbers. In this paper, we give combinatorial interpretations for these numbers when $m=2$ or 3.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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