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arXiv 2403.09082math.CO
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无单色三角形意味着各种适当着色的生成树

The absence of monochromatic triangle implies various properly colored spanning trees

Northwestern Polytechnical University(西北工业大学)

Ruonan Li, Ruhui Lu, Xueli Su, Shenggui Zhang

AI总结:

研究探讨了在无单色三角形的完全图中存在适当着色生成树的条件,证明了星型树的猜想,并探讨了相关Ramsey数的量化估计。

摘要:

一个边着色图G被称为适当着色的,如果相邻边有不同的颜色。单色三角形是指长度为3的环,所有边颜色相同。给定一个树T₀,令T(n,T₀)表示n个顶点的树,是T₀的细分。猜想指出,对于每个固定树T₀,存在函数f(T₀),使得对于每个整数n≥f(T₀)和每个T∈T(n,T₀),每个不含单色三角形的边着色完全图Kₙ必须包含一个适当着色的T的副本。我们证明了当T₀是星型树时的猜想。还获得了上述猜想的较弱版本。此外,为了获得当T₀是星型树时f(T₀)的量化估计,需要确定单色三角形和彩虹星型树的限制Ramsey数,这具有独立的研究价值。

英文摘要:

An edge-colored graph $G$ is called properly colored if every two adjacent edges are assigned different colors. A monochromatic triangle is a cycle of length 3 with all the edges having the same color. Given a tree $T_0$, let $\mathcal{T}(n,T_0)$ be the collection of $n$-vertex trees that are subdivisions of $T_0$. It is conjectured that for each fixed tree $T_0$, there is a function $f(T_0)$ such that for each integer $n\geq f(T_0)$ and each $T\in \mathcal{T}(n,T_0)$, every edge-colored complete graph $K_n$ without containing monochromatic triangle must contain a properly colored copy of $T$. We confirm the conjecture in the case that $T_0$ is a star. A weaker version of the above conjecture is also obtained. Moreover, to get a nice quantitative estimation of $f(T_0)$ when $T_0$ is a star requires determining the constraint Ramsey number of a monochromatic triangle and a rainbow star, which is of independent interest.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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