arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 2301.06012math.COcs.ITmath.IT
收藏

关于非退化线性$[n,2]_2$码的图

On the graph of non-degenerate linear $[n,2]_2$ codes

Mark Pankov

摘要:

考虑$q$元域$1<k<n-1$上$n$维向量空间的$k$维子空间的格拉斯曼图.这个图的每一个自同构都是由相应向量空间的半线性自同构或对偶向量空间的半线性同构导出的;第二种可能性只对$n=2k$实现。设$Γ(n,k)_q$是由所有非退化线性$[n,k]_q$码构成的Grassman图的子图.如果$q\ge 3$或$k\ge 3$,则$Γ(n,k)_{q}$到Grassmann图的一个子图的每一个同构都可以唯一地扩展到Grassmann图的一个自同构.对于$q=k=2$,存在$Γ(n,k)_{q}$到Grassmann图的一个不具有此性质的子图的同构。在本文中,我们证明了这种特殊的同构是唯一的自同构的格拉斯曼图。

英文摘要:

Consider the Grassmann graph of $k$-dimensional subspaces of an $n$-dimensional vector space over the $q$-element field, $1<k<n-1$. Every automorphism of this graph is induced by a semilinear automorphism of the corresponding vector space or a semilinear isomorphism to the dual vector space; the second possibility is realized only for $n=2k$. Let $Γ(n,k)_q$ be the subgraph of the Grassman graph formed by all non-degenerate linear $[n,k]_q$ codes. If $q\ge 3$ or $k\ge 3$, then every isomorphism of $Γ(n,k)_{q}$ to a subgraph of the Grassmann graph can be uniquely extended to an automorphism of the Grassmann graph. For $q=k=2$ there is an isomorphism of $Γ(n,k)_{q}$ to a subgraph of the Grassmann graph which does not have this property. In this paper, we show that such exceptional isomorphism is unique up to an automorphism of the Grassmann graph.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑