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arXiv 1504.05786math.CA
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关于部分θ函数的双零点

On the double zeros of a partial theta function

Vladimir Petrov Kostov

摘要:

级数$θ(q,x):=\sum _{j=0}^{\infty}q^{j(j+1)/2}x^j$收敛于$q\in [0,1)$、$x\in \mathbb{R}$,并定义了{ \em部分θ函数}。对于任何固定的$q\in (0,1)$,它有无穷多个负零。对于取{ \em谱}值$\tilde{q}_1$、$\tilde{q}_2$、$\ldots$(其中$0.3092493386\ldots =\tilde{q}_1<\tilde{q}_2<\cdots <1$、$\lim _{j\rightarrow \infty}\tilde{q}_j=1$)之一的$q$,函数$θ(q,.)$有一个双零$y_j$,它是它的最右边的实零点(其余的是简单的)。对于$q\neq \tilde{q}_j$,部分θ函数没有多个实零点。我们证明了$\tilde{q}_j=1-π/2j+(\log j)/8j^2+O(1/j^2)$和$y_j=-e^πe^{-(\log j)/4j+O(1/j)}$ .

英文摘要:

The series $θ(q,x):=\sum _{j=0}^{\infty}q^{j(j+1)/2}x^j$ converges for $q\in [0,1)$, $x\in \mathbb{R}$, and defines a {\em partial theta function}. For any fixed $q\in (0,1)$ it has infinitely many negative zeros. For $q$ taking one of the {\em spectral} values $\tilde{q}_1$, $\tilde{q}_2$, $\ldots$ (where $0.3092493386\ldots =\tilde{q}_1<\tilde{q}_2<\cdots <1$, $\lim _{j\rightarrow \infty}\tilde{q}_j=1$) the function $θ(q,.)$ has a double zero $y_j$ which is the rightmost of its real zeros (the rest of them being simple). For $q\neq \tilde{q}_j$ the partial theta function has no multiple real zeros. We prove that $\tilde{q}_j=1-π/2j+(\log j)/8j^2+O(1/j^2)$ and $y_j=-e^πe^{-(\log j)/4j+O(1/j)}$.

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