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arXiv 1502.04680math.APmath.DG
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关于Serrin超定问题及Berestycki,Caffarelli和Nirenberg的一个猜想

On Serrin's overdetermined problem and a conjecture of Berestycki, Caffarelli and Nirenberg

Kelei Wang, Juncheng Wei

摘要:

本文讨论了在epigraph $$ \{\begin{aligned} &Δu+ f(u)=0,\ \ \ {in}\ Ω=\{(x^\prime,x_n): x_n>φ(x^\prime)\},\\ &u>0,\ \ \ {in}\ Ω,\\ &u=0,\ \ \ {on}\ \partialΩ,\\ &|\nabla u|=const. {on} \partialΩ. \end{aligned}. $$中Serrin超定问题的刚性结果。我们证明了在等距的情况下epigraph必须是半空间,并且解$u$必须是一维的,只要满足下列假设之一:$n=2$ ;或$ φ$是全局Lipschitz,或$n \leq 8$和$ \frac{\partial u}{\partial x_n} >0$在$Ω$中。考虑到在\cite{DPW}中构造的维数为$n\geq 9$的反例,该结果是最优的。这部分回答了Berestycki,Caffarelli和Nirenberg \cite{BCN}的一个猜想。

英文摘要:

This paper concerns rigidity results to Serrin's overdetermined problem in an epigraph $$ \{\begin{aligned} &Δu+ f(u)=0,\ \ \ {in}\ Ω=\{(x^\prime,x_n): x_n>φ(x^\prime)\},\\ &u>0,\ \ \ {in}\ Ω,\\ &u=0,\ \ \ {on}\ \partialΩ,\\ &|\nabla u|=const. {on} \partialΩ. \end{aligned}. $$ We prove that up to isometry the epigraph must be an half space and that the solution $u$ must be one-dimensional, provided that one of the following assumptions are satisfied: either $n=2$; or $ φ$ is globally Lipschitz, or $n \leq 8$ and $ \frac{\partial u}{\partial x_n} >0$ in $Ω$. In view of the counterexample constructed in \cite{DPW} in dimensions $n\geq 9$ this result is optimal. This partially answers a conjecture of Berestycki, Caffarelli and Nirenberg \cite{BCN}.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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