Properties of intervals in the lattice of antichains of subsets of a universe of finite size are investigated. New objects and quantities in this lattice are defined. Expressions and numerical values are deduced for the number of connected antichains and the number of fully distinguishing antichains. The latter establish a connection with Stirling numbers of the second kind. Decomposition properties of intervals in the lattice of antichains are proven. A new operator allowing partitioning the full lattice in intervals derived from lower dimensional sub-lattices is introduced. Special posets underlying an interval of antichains are defined. The poset allows the derivation of a powerful formula for the size of an interval. This formula allows computing intervals in the six dimensional space. Combinatorial coefficients allowing another decomposition of the full lattice are defined. In some specific cases, related to connected components in graphs, these coefficients can be efficiently computed. This formula allows computing the size of the lattice of order 8 efficiently. This size is the number of Dedekind of order 8, the largest one known so far.
Hasse diagrams of posets with up to 7 elements, and the number of posets with 10 elements, without the use of computer programs
设$P(n)$是所有具有$n$元素的偏序集的集合。令$P^{(j)}(n)$,$1\leq j\leq 2^n,$为具有恰好具有$j$反链的$n$元素的所有偏序集的数目。我们确定了数$P^{(j)}(7),$ $1\leq j\leq 128$,并利用M.~ Erné [Erné,M.,On the cardinalities of finite topologies and the number of antichains in partially ordered sets,Discrete Mathematics 35(1981),119-133.我们在没有任何计算机程序的帮助下计算$|P(10)|$。我们包含了$P(7)$的所有非同构偏序集的Hasse图。我们还提出了某些形式的连通偏序集的数量的公式,并使用它们来计算$|P(n)|$与$1\le n\le 8$通过不同的方法。
Generalized degrees and densities for families of sets
设F是{1,2,…,n}。在F的至少一个成员中的元素x的宽度是族{U in F}的宽度|x in U}。如果F的最大宽度度不超过k,则F是局部k宽的。建立了局部k宽集合族的大小的界。如果F是局部k-宽且中心的(F中的每个U都有一个元素不属于F中与U不可比的任何成员),则|F| <=(k+1)(n-k/2);此界是最佳可能的。几乎精确的界限,线性n和k,局部k-宽家庭的弧或段的大小确定。若F是任意局部k-宽集合族,则|F|在n中线性有界.这个结果的证明涉及反链的组合学分析。设P是偏序集,L是半格(或交闭集族)。L的P大小为|L^P|.对于L中的u,u的P-密度是|[u]^P|/|L^P|. u的密度由u的[1]-密度给出。设p是P的滤子个数,L具有P-密度性当且仅当存在L中的并不可约a使得a的P-密度至多为1/p哪些非平凡半格具有P-密度性?对于P=[1],已经证明了答案是:“所有”(并闭集猜想)。下半模格和几何格(P=[n])的某些次直积具有强意义下的P-稠密性。这推广了一些以前已知的结果。如果n足够大,则固定格具有[n]-密度性质。估计了包含该空集的并闭集族L的生成元U的密度。该估计仅依赖于L在U处的局部性质。如果L是由大小至多为2的集合生成的,则存在L的生成元U,其估计密度至多为1/2。