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arXiv 1402.6424math.OAmath.FA
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Hilbert C*-模的内积与模映射

Inner products and module maps of Hilbert C*-modules

Ming-Hsiu Hsu, Ngai-Ching Wong

摘要:

设$E$和$F$分别是$C^*$ -代数$A$和$B$上的两个Hilbert $C^*$ -模.设$T$是从$E$到$F$的满射线性等距,$φ$是从$A$到$B$的映射。本文证明了:如果$C^*$ -代数$A$和$B$是可交换的,则$T$保持内积且$T$是模映射,即,在$C^*$ -代数之间存在$*$ -同构$φ$,使得$$ \langle Tx,Ty\rangle=φ(\langle x,y\rangle), $$和$$ T(xa)=T(x)φ(a). $$在$A$或$B$是非交换$C^*$ -代数的情况下,$T$通常可能不满足上面的等式。给出了$T$保持内积和$T$是模映射的条件。

英文摘要:

Let $E$ and $F$ be two Hilbert $C^*$-modules over $C^*$-algebras $A$ and $B$, respectively. Let $T$ be a surjective linear isometry from $E$ onto $F$ and $φ$ a map from $A$ into $B$. We will prove in this paper that if the $C^*$-algebras $A$ and $B$ are commutative, then $T$ preserves the inner products and $T$ is a module map, i.e., there exists a $*$-isomorphism $φ$ between the $C^*$-algebras such that $$ \langle Tx,Ty\rangle=φ(\langle x,y\rangle), $$ and $$ T(xa)=T(x)φ(a). $$ In case $A$ or $B$ is noncommutative $C^*$-algebra, $T$ may not satisfy the equations above in general. We will also give some condition such that $T$ preserves the inner products and $T$ is a module map.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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