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arXiv 1012.1394math.AC
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平坦模复形的无环性

Acyclicity of complexes of flat modules

Mitsuyasu Hashimoto

摘要:

设$R$是Noether交换环,\[ \mathbb F: ...\rightarrow F_2\rightarrow F_1\rightarrow F_0\rightarrow 0 \]是平坦$R$ -模复形.证明了如果对每个$\mathfrak p\in\Spec R$,$κ(\mathfrak p)\otimes_R\mathbb F$是无圈的,则$\mathbb F$是无圈的,并且$H_0(\mathbb F)$是$R$ -平坦的.因此,如果$\mathbb F$是平坦$R$ -模的(可能无界的)复形,并且$κ(\mathfrak p)\otimes_R \mathbb F$对于每个$\mathfrak p\in\Spec R$是精确的,则$\mathbb G\otimes_R^\bullet\mathbb F$对于每个$R$ -复形$\mathbb G$是精确的。此外,如果$\mathbb F$是投射$R$ -模的复形,则它是零同伦的(由尼曼定理得出)。

英文摘要:

Let $R$ be a noetherian commutative ring, and \[ \mathbb F: ...\rightarrow F_2\rightarrow F_1\rightarrow F_0\rightarrow 0 \] a complex of flat $R$-modules. We prove that if $κ(\mathfrak p)\otimes_R\mathbb F$ is acyclic for every $\mathfrak p\in\Spec R$, then $\mathbb F$ is acyclic, and $H_0(\mathbb F)$ is $R$-flat. It follows that if $\mathbb F$ is a (possibly unbounded) complex of flat $R$-modules and $κ(\mathfrak p)\otimes_R \mathbb F$ is exact for every $\mathfrak p\in\Spec R$, then $\mathbb G\otimes_R^\bullet\mathbb F$ is exact for every $R$-complex $\mathbb G$. If, moreover, $\mathbb F$ is a complex of projective $R$-modules, then it is null-homotopic (follows from Neeman's theorem).

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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