Proof of the Double Bubble Conjecture
英文摘要:
We prove that the standard double bubble provides the least-area way to enclose and separate two regions of prescribed volume in \Bbb R^3.
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Michael Hutchings, Frank Morgan, Manuel Ritoré, Antonio Ros
We prove that the standard double bubble provides the least-area way to enclose and separate two regions of prescribed volume in \Bbb R^3.
机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。
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The classic double bubble theorem says that the least-perimeter way to enclose and separate two prescribed volumes in $\mathbb{R}^N$ is the standard double bubble. We seek the optimal double bubble in $\mathbb{R}^N$ with density, which we assume to be strictly log-convex. For $N=1$ we show that the solution is sometimes two contiguous intervals and sometimes three contiguous intervals. In higher dimensions, we think that the solution is sometimes a standard double bubble and sometimes concentric spheres (e.g. for one volume small and the other large).
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The Structure of Isoperimetric Bubbles on $\mathbb{R}^n$ and $\mathbb{S}^n$
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The classical isoperimetric inequality in R^3 states that the surface of smallest area enclosing a given volume is a sphere. We show that the least area surface enclosing two equal volumes is a double bubble, a surface made of two pieces of round spheres separated by a flat disk, meeting along a single circle at an angle of 120 degrees.
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An Infinite Double Bubble Theorem
本文证明了双气泡定理的一个变体,其中两个腔室具有无穷体积,证明了加权透镜簇是局部最小化的,并在特定对称性和增长假设下确立了其唯一性,同时得到了局部最小化 (N,2)-cluster 的闭包定理。
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It is shown that $3$ disjoint sets with fixed Gaussian volumes that partition $\mathbb{R}^{n}$ with nearly minimum total Gaussian surface area must be close to adjacent $120$ degree sectors, when $n\geq2$. These same results hold for any number $m\leq n+1$ of sets partitioning $\mathbb{R}^{n}$, conditional on the solution of a finite-dimensional optimization problem (similar to the endpoint case of the Plurality is Stablest Problem, or the Propeller Conjecture of Khot and Naor). When $m>3$, the minimal Gaussian surface area is achieved by the cones over a regular simplex. We therefore strength…
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