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arXiv math/0202231math.CO
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多分支完全一致超图的边染色

Edge coloring complete uniform hypergraphs with many components

Yair Caro, Raphael Yuster

摘要:

设$H$是一个超图。对于$k$ -边着色$c : E(H) \to \{1,...,k\}$,令$f(H,c)$为由具有最少分量的色类导出的子超图中的分量数.令$f_k(H)$为$H$的所有$k$ -边着色范围内的$f(H,c)$的最大可能值。如果$H$是完全图$K_n$,那么简单地说,就是$f_1(K_n)=f_2(K_n)=1$。本文证明了对于$n \geq 6$,$f_3(K_n)=\lfloor n/6 \rfloor+1$,并给出了$k \geq 4$情形下$f_k(K_n)$的上下界.还建立了关于$f_k(K_n^r)$的值的几个结果,其中$K_n^r$是$n$顶点上的完全$r$ -一致超图.

英文摘要:

Let $H$ be a hypergraph. For a $k$-edge coloring $c : E(H) \to \{1,...,k\}$ let $f(H,c)$ be the number of components in the subhypergraph induced by the color class with the least number of components. Let $f_k(H)$ be the maximum possible value of $f(H,c)$ ranging over all $k$-edge colorings of $H$. If $H$ is the complete graph $K_n$ then, trivially, $f_1(K_n)=f_2(K_n)=1$. In this paper we prove that for $n \geq 6$, $f_3(K_n)=\lfloor n/6 \rfloor+1$ and supply close upper and lower bounds for $f_k(K_n)$ in case $k \geq 4$. Several results concerning the value of $f_k(K_n^r)$, where $K_n^r$ is the complete $r$-uniform hypergraph on $n$ vertices, are also established.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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