arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 2601.04084math.CO

精确禁止配置的界限及极值矩阵

Exact Bounds for Forbidden Configurations and the Extremal Matrices

Richard P. Anstee, Oakley Edens, Arvin Sahami, Jaehwan Seok, Attila Sali

AI总结:

本文研究了禁止特定配置的矩阵极值问题,确定了特定配置下的最大列数,并刻画了极值矩阵的构造方法。

摘要:

设F为一个k×ℓ的(0,1)-矩阵。如果一个矩阵的列不重复,则称为简单矩阵。一个(0,1)-矩阵A如果包含F作为配置,则意味着A中存在一个子矩阵是F的行和列排列。在集合语言中,配置称为痕迹。设Avoid(m,F)为所有m行的简单矩阵A,其中不包含配置F。定义forb(m,F)为Avoid(m,F)中任意矩阵的最大列数。2×(p+1)的(0,1)-矩阵F(0,p,1,0)由一行p个1和一行一个1组成。本文确定了forb(m,F(0,p,1,0))在1≤p≤9时的值,并且极值矩阵被刻画。一种构造可能对所有p都有效。

英文摘要:

Let $F$ be a $k\times \ell$ (0,1)-matrix. A matrix is simple if it is a (0,1)-matrix with no repeated columns. A (0,1)-matrix $A$ is said to have a $F$ as a configuration if there is a submatrix of $A$ which is a row and column permutation of $F$. In the language of sets, a configuration is a trace. Let $\mathrm{Avoid}(m,F)$ be all simple $m$-rowed matrices $A$ with no configuration $F$. Define $\mathrm{forb}(m,F)$ as the maximum number of columns of any matrix in $\mathrm{Avoid}(m,F)$. The $2\times (p+1)$ (0,1)-matrix $F(0,p,1,0)$ consists of a row of $p$ 1's and a row of one 1 in the remaining column. The paper determines $\mathrm{forb}(m,F(0,p,1,0))$ for $1\le p\le 9$ and the extremal matrices are characterized. A construction may be extremal for all $p$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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