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arXiv 2302.00630cs.DS
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有色聚类的参数化算法

Parameterized Algorithms for Colored Clustering

Leon Kellerhals, Tomohiro Koana, Pascal Kunz, Rolf Niedermeier

摘要:

在着色聚类问题中,要求对边着色(超)图进行聚类,其颜色表示交互类型。更具体地说,目标是选择尽可能多的边,而不选择共享端点且颜色不同的两条边。同样,目标也可以被描述为以尽可能适合边着色的方式为顶点分配颜色。由于这个问题是NP难的,我们建立在以前的工作,研究其参数化的复杂性。我们给出了一个$2^{\mathcal O(k)} \cdot n^{\mathcal O(1)}$ -时间算法,其中$k$是要选择的边数,$n$是顶点数.我们还证明了存在的问题内核的大小$\mathcal O(k^{5/2} )$,解决一个公开的问题,在文献中提出的。我们考虑小于$k$(要选择的边数)和$r$(可以删除的边数)的参数。通过考虑$k$或$r$之间的差异以及这些值的某个下限来获得这些较小的参数。我们给这两个算法和下界的彩色聚类等参数化。最后,我们解决了颜色聚类的结构图参数的参数化的复杂性,通过显示它是$W[1]$ -硬的顶点覆盖数和树切割宽度,但固定参数听话的超薄树切割宽度。

英文摘要:

In the Colored Clustering problem, one is asked to cluster edge-colored (hyper-)graphs whose colors represent interaction types. More specifically, the goal is to select as many edges as possible without choosing two edges that share an endpoint and are colored differently. Equivalently, the goal can also be described as assigning colors to the vertices in a way that fits the edge-coloring as well as possible. As this problem is NP-hard, we build on previous work by studying its parameterized complexity. We give a $2^{\mathcal O(k)} \cdot n^{\mathcal O(1)}$-time algorithm where $k$ is the number of edges to be selected and $n$ the number of vertices. We also prove the existence of a problem kernel of size $\mathcal O(k^{5/2} )$, resolving an open problem posed in the literature. We consider parameters that are smaller than $k$, the number of edges to be selected, and $r$, the number of edges that can be deleted. Such smaller parameters are obtained by considering the difference between $k$ or $r$ and some lower bound on these values. We give both algorithms and lower bounds for Colored Clustering with such parameterizations. Finally, we settle the parameterized complexity of Colored Clustering with respect to structural graph parameters by showing that it is $W[1]$-hard with respect to both vertex cover number and tree-cut width, but fixed-parameter tractable with respect to slim tree-cut width.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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