arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 2103.06801cs.CG
收藏

具有三个或更多坡度的向上平面图

Upward Planar Drawings with Three and More Slopes

Jonathan Klawitter, Johannes Zink

摘要:

图形$G$的斜率数是表示$G$的任何直线图形中的边的线段所需的最小斜率数。它作为图形绘制的视觉复杂性的度量。在平面和非平面环境中,已经建立了几个特定图形类的斜率数的界限。此外,也可以为有向图和向上平面图定义斜率数。我们研究只使用常数斜率的向上平面直线绘图。特别是,对于一个固定数量的$k$的斜坡,我们感兴趣的是,是否一个给定的有向图$G$与最大的在和出度最多$k$承认一个向上的平面$k$ -斜坡绘图。我们调查这个问题,在固定和可变嵌入的情况下。我们证明了这个问题对于外平面图($k = 3$)和平面图($k \ge 3$)是NP-难判定的。在积极的一面,我们可以决定是否一个给定的仙人掌图允许向上的平面$k$ -斜坡图,并在肯定的情况下,构造这样一个图在FPT时间与参数$k$。此外,我们可以确定线性时间内给定树所需的最小斜率数,并有效地计算相应的绘图。

英文摘要:

The slope number of a graph $G$ is the smallest number of slopes needed for the segments representing the edges in any straight-line drawing of $G$. It serves as a measure of the visual complexity of a graph drawing. Several bounds on the slope number for particular graph classes have been established, both in the planar and the non-planar setting. Moreover, the slope number can also be defined for directed graphs and upward planar drawings. We study upward planar straight-line drawings that use only a constant number of slopes. In particular, for a fixed number $k$ of slopes, we are interested in whether a given directed graph $G$ with maximum in- and outdegree at most $k$ admits an upward planar $k$-slope drawing. We investigate this question both in the fixed and the variable embedding scenario. We show that this problem is in general NP-hard to decide for outerplanar graphs ($k = 3$) and planar graphs ($k \ge 3$). On the positive side, we can decide whether a given cactus graph admits an upward planar $k$-slope drawing and, in the affirmative, construct such a drawing in FPT time with parameter $k$. Furthermore, we can determine the minimum number of slopes required for a given tree in linear time and compute the corresponding drawing efficiently.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑