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arXiv 2102.07573math.NT
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椭圆可除序列的一个递推关系

A recurrence relation for elliptic divisibility sequences

Matteo Verzobio

AI总结:

本文针对椭圆可除序列的两种非等价定义,证明在索引满足特定条件时,分母平方根序列也满足经典递推关系。

摘要:

文献中存在椭圆可除序列的两种不同定义。第一种定义称整数序列$\{h_n\}_{n\geq 0}$为椭圆可除序列,若它对每个自然数$m\geq n\geq r$满足递推关系$h_{m+n}h_{m-n}h_{r}^2=h_{m+r}h_{m-r}h_{n}^2-h_{n+r}h_{n-r}h_{m}^2$。第二种定义称整数序列$\{\beta_n\}_{n\geq 0}$为椭圆可除序列,若它是有理椭圆曲线上一点迭代的横坐标的分母(按适当符号选取)的平方根序列。众所周知,这两种序列并不等价。因此,给定一个分母序列$\{\beta_n\}_{n\geq 0}$,一般情况下$m\geq n\geq r$时$\beta_{m+n}\beta_{m-n}\beta_{r}^2=\beta_{m+r}\beta_{m-r}\beta_{n}^2-\beta_{n+r}\beta_{n-r}\beta_{m}^2$并不成立。我们将证明,在索引$m$、$n$和$r$的某些条件下,上述递推关系对$\{\beta_n\}_{n\geq 0}$成立。

英文摘要:

In literature, there are two different definitions of elliptic divisibility sequences. The first one says that a sequence of integers $\{h_n\}_{n\geq 0}$ is an elliptic divisibility sequence if it verifies the recurrence relation $h_{m+n}h_{m-n}h_{r}^2=h_{m+r}h_{m-r}h_{n}^2-h_{n+r}h_{n-r}h_{m}^2$ for every natural number $m\geq n\geq r$. The second definition says that a sequence of integers $\{β_n\}_{n\geq 0}$ is an elliptic divisibility sequence if it is the sequence of the square roots (chosen with an appropriate sign) of the denominators of the abscissas of the iterates of a point on a rational elliptic curve. It is well-known that the two sequences are not equivalent. Hence, given a sequence of the denominators $\{β_n\}_{n\geq 0}$, in general does not hold $β_{m+n}β_{m-n}β_{r}^2=β_{m+r}β_{m-r}β_{n}^2-β_{n+r}β_{n-r}β_{m}^2$ for $m\geq n\geq r$. We will prove that the recurrence relation above holds for $\{β_n\}_{n\geq 0}$ under some conditions on the indexes $m$, $n$, and $r$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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