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arXiv 2005.14466math.NT
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Guo和Schlosser证明的一个q-超同余

Proof of a q-supercongruence conjectured by Guo and Schlosser

Long Li, Su-Dan Wang

摘要:

本文证明了Guo和Schlosser的猜想:对任意奇数$n>1$和$M=(n+1)/2$或$n-1$,有$$ \sum_{k=0}^{M}[4k-1]_{q^2}[4k-1]^2\frac{(q^{-2};q^4)_k^4}{(q^4;q^4)_k^4}q^{4k}\equiv (2q+2q^{-1}-1)[n]_{q^2}^4\pmod{[n]_{q^2}^4Φ_n(q^2)}, $$其中$[n]=[n]_q=(1-q^n)/(1-q),(a;q)_0=1,(a;q)_k=(1-a)(1-aq)\cdots(1-aq^{k-1})$对$k\geq 1$和$Φ_n(q)$表示$n$ -次分圆多项式.

英文摘要:

In this paper, we confirm the following conjecture of Guo and Schlosser: for any odd integer $n>1$ and $M=(n+1)/2$ or $n-1$, $$ \sum_{k=0}^{M}[4k-1]_{q^2}[4k-1]^2\frac{(q^{-2};q^4)_k^4}{(q^4;q^4)_k^4}q^{4k}\equiv (2q+2q^{-1}-1)[n]_{q^2}^4\pmod{[n]_{q^2}^4Φ_n(q^2)}, $$ where $[n]=[n]_q=(1-q^n)/(1-q),(a;q)_0=1,(a;q)_k=(1-a)(1-aq)\cdots(1-aq^{k-1})$ for $k\geq 1$ and $Φ_n(q)$ denotes the $n$-th cyclotomic polynomial.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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