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arXiv 2004.10528math.NT
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两个连续素数之间的间隙$g_n$满足$g_n=O({p_n}^{2/3})$

The gap $g_n$ between two consecutive primes satisfies $g_n=O({p_n}^{2/3})$

Madieyna Diouf

摘要:

下面的证明使用的论点,不围绕黎曼假设或筛理论。如果$p_n$是$n^{\rm th}$素数和$g_n=p_{n+1}-p_n$,则为$g_n=O({p_n}^{2/3})$。

英文摘要:

The following is proven using arguments that do not revolve around the Riemann Hypothesis or Sieve Theory. If $p_n$ is the $n^{\rm th}$ prime and $g_n=p_{n+1}-p_n$, then $g_n=O({p_n}^{2/3})$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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