arXivDaily arXiv每日学术速递 周一至周五更新
arXiv 2004.08714math.COcs.DM
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几乎相交族

Almost intersecting families

Peter Frankl, Andrey Kupavskii

摘要:

令$n > k > 1$为整数,$[n] = \{1, \ldots, n\}$。设$\mathcal F$是~ $[n]$的$k$ -子集族.如果所有$F, F' \in \mathcal F$都有$F \cap F' \neq \emptyset$,则族$\mathcal F$称为相交。如果它不相交,但对于每个$F \in \mathcal F$,最多有一个$F'\in \mathcal F$满足$F \cap F' = \emptyset$,则称为几乎相交。Gerbner等人证明,如果$n \geq 2k + 2$,则$|\mathcal F| \leq {n - 1\choose k - 1}$对几乎相交族成立。主要结果暗示了$n > (2 + o(1))k$的相当强的和最好的可能界$|\mathcal F| \leq {n - 1\choose k - 1} - {n - k - 1\choose k - 1} + 2$。

英文摘要:

Let $n > k > 1$ be integers, $[n] = \{1, \ldots, n\}$. Let $\mathcal F$ be a family of $k$-subsets of~$[n]$. The family $\mathcal F$ is called intersecting if $F \cap F' \neq \emptyset$ for all $F, F' \in \mathcal F$. It is called almost intersecting if it is not intersecting but to every $F \in \mathcal F$ there is at most one $F'\in \mathcal F$ satisfying $F \cap F' = \emptyset$. Gerbner et al. proved that if $n \geq 2k + 2$ then $|\mathcal F| \leq {n - 1\choose k - 1}$ holds for almost intersecting families. The main result implies the considerably stronger and best possible bound $|\mathcal F| \leq {n - 1\choose k - 1} - {n - k - 1\choose k - 1} + 2$ for $n > (2 + o(1))k$.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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