arXivDaily arXiv每日学术速递 周一至周五更新
arXiv周末暂无论文更新,休息一下吧,周末愉快~~
arXiv 1709.02829math.COcs.DM
收藏

一致相交族的多样性

Diversity of uniform intersecting families

Andrey Kupavskii

摘要:

如果族$\mathcal F\subset 2^{[n]}$的任何两个集合相交,则该族称为相交族。给定一个相交族,它的多样性是不通过基集的最流行元素的集合的数量。Peter Frankl提出了如下猜想:对于$n> 3k>0$,任何相交的家族$\mathcal F\subset {[n]\choose k}$最多有${n-3\choose k-2}$的多样性。这对于以下“三选二”系列是严格的:$\{F\in {[n]\choose k}: |F\cap [3]|\ge 2\}$。本文对$n\ge ck$证明了这个猜想,其中$c$是与$n$和$k$无关的常数.在最后一节中,我们讨论了$2k<n<3k$的情况,并证明了一个自然推广的Frankl猜想不成立。

英文摘要:

A family $\mathcal F\subset 2^{[n]}$ is called intersecting if any two of its sets intersect. Given an intersecting family, its diversity is the number of sets not passing through the most popular element of the ground set. Peter Frankl made the following conjecture: for $n> 3k>0$ any intersecting family $\mathcal F\subset {[n]\choose k}$ has diversity at most ${n-3\choose k-2}$. This is tight for the following "two out of three" family: $\{F\in {[n]\choose k}: |F\cap [3]|\ge 2\}$. In this note, we prove this conjecture for $n\ge ck$, where $c$ is a constant independent of $n$ and $k$. In the last section, we discuss the case $2k<n<3k$ and show that one natural generalization of Frankl's conjecture does not hold.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

↑