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arXiv 2002.00613math.AP
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具有临界Sobolev指数的curl-curl方程的基态和旋度算子的Sobolev型不等式

A Sobolev-type inequality for the curl operator and ground states for the curl-curl equation with critical Sobolev exponent

Jarosław Mederski, Andrzej Szulkin

备注：
Archive for Rational Mechanics and Analysis (2021)
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摘要：

令$Ω\subset \mathbb{R}^3$是Lipschitz域，并令$S_\mathrm{curl}(Ω)$是最大常数，使得对于$W_0^6(\mathrm{curl};Ω)\subset W_0^6(\mathrm{curl};\mathbb{R}^3)$中的任何$u$，都有$$ \int_{\mathbb{R}^3}|\nabla\times u|^2\, dx\geq S_{\mathrm{curl}}(Ω) \inf_{\substack{w\in W_0^6(\mathrm{curl};\mathbb{R}^3)\\ \nabla\times w=0}}\Big(\int_{\mathbb{R}^3}|u+w|^6\,dx\Big)^{\frac13} $$，其中$W_0^6(\mathrm{curl};Ω)$是$\{u\in L^6(Ω,\mathbb{R}^3): \nabla\times u\in L^2(Ω,\mathbb{R}^3)\}$中的$\mathcal{C}_0^{\infty}(Ω,\mathbb{R}^3)$关于范数$(|u|_6^2+|\nabla\times u|_2^2)^{1/2}$的闭包。我们发现，$S_{\mathrm{curl}}(Ω)$是严格大于经典的Sobolev常数$S$在$\mathbb{R}^3$。此外，$S_{\mathrm{curl}}(Ω)$是独立的$Ω$和获得的基态解决方案的卷曲卷曲问题$$ \nabla\times (\nabla\times u) = |u|^4u $$，如果$Ω=\mathbb{R}^3$。借助这些结果，我们还研究了有界区域$Ω$ $$\nabla\times (\nabla\times u) +λu = |u|^4u\quad\hbox{in }Ω$$中curl-curl算子的Brezis-Nirenberg型问题的基态，其中$ν$是$\partialΩ$的外法线，具有所谓的金属边界条件$ν\times u=0$.

英文摘要：

Let $Ω\subset \mathbb{R}^3$ be a Lipschitz domain and let $S_\mathrm{curl}(Ω)$ be the largest constant such that $$ \int_{\mathbb{R}^3}|\nabla\times u|^2\, dx\geq S_{\mathrm{curl}}(Ω) \inf_{\substack{w\in W_0^6(\mathrm{curl};\mathbb{R}^3)\\ \nabla\times w=0}}\Big(\int_{\mathbb{R}^3}|u+w|^6\,dx\Big)^{\frac13} $$ for any $u$ in $W_0^6(\mathrm{curl};Ω)\subset W_0^6(\mathrm{curl};\mathbb{R}^3)$ where $W_0^6(\mathrm{curl};Ω)$ is the closure of $\mathcal{C}_0^{\infty}(Ω,\mathbb{R}^3)$ in $\{u\in L^6(Ω,\mathbb{R}^3): \nabla\times u\in L^2(Ω,\mathbb{R}^3)\}$ with respect to the norm $(|u|_6^2+|\nabla\times u|_2^2)^{1/2}$. We show that $S_{\mathrm{curl}}(Ω)$ is strictly larger than the classical Sobolev constant $S$ in $\mathbb{R}^3$. Moreover, $S_{\mathrm{curl}}(Ω)$ is independent of $Ω$ and is attained by a ground state solution to the curl-curl problem $$ \nabla\times (\nabla\times u) = |u|^4u $$ if $Ω=\mathbb{R}^3$. With the aid of those results, we also investigate ground states of the Brezis-Nirenberg-type problem for the curl-curl operator in a bounded domain $Ω$ $$\nabla\times (\nabla\times u) +λu = |u|^4u\quad\hbox{in }Ω$$ with the so-called metallic boundary condition $ν\times u=0$ on $\partialΩ$, where $ν$ is the exterior normal to $\partialΩ$.

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