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arXiv 2002.00483math.COcs.DM
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三片和四片叶子上的毛虫足以重建正常的网络

Caterpillars on three and four leaves are sufficient to reconstruct normal networks

Simone Linz, Charles Semple

摘要:

虽然每个有根二元系统发生树是由其显示的有根三元组的集合确定的,但这样的结果不适用于任意有根二元系统发生网络。特别地,存在两个非同构的有根二元时间正规网络,它们显示相同的有根三元组集合。此外,没有任何结构上的限制,根系统发育网络的考虑,类似的负面结果也已经建立了binets和trademark,这是植根于两个和三个叶子,分别子网络。因此,一般来说,从这样一组小的构建块拼凑出一个有根的系统发育网络似乎是不可逾越的。与这些结果相反,在本文中,我们证明了一个有根的二进制正常网络是由它的集显示毛毛虫(特定类型的子树)上的三个和四个叶子。证明是建设性的,并实现了一个多项式时间算法,采取集的毛毛虫的三个和四个叶子显示的一个有根二进制正常的网络,同构,重建这个网络。

英文摘要:

While every rooted binary phylogenetic tree is determined by its set of displayed rooted triples, such a result does not hold for an arbitrary rooted binary phylogenetic network. In particular, there exist two non-isomorphic rooted binary temporal normal networks that display the same set of rooted triples. Moreover, without any structural constraint on the rooted phylogenetic networks under consideration, similarly negative results have also been established for binets and trinets which are rooted subnetworks on two and three leaves, respectively. Hence, in general, piecing together a rooted phylogenetic network from such a set of small building blocks appears insurmountable. In contrast to these results, in this paper, we show that a rooted binary normal network is determined by its sets of displayed caterpillars (particular type of subtrees) on three and four leaves. The proof is constructive and realises a polynomial-time algorithm that takes the sets of caterpillars on three and four leaves displayed by a rooted binary normal network and, up to isomorphism, reconstructs this network.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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