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arXiv 1908.03169math.COcs.FL
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二元富词的重复阈值

The repetition threshold for binary rich words

James D. Currie, Lucas Mol, Narad Rampersad

AI总结:

本文证明二元富词的重复阈值为 $2+\sqrt{2}/2$,通过结构定理验证了 Baranwal 和 Shallit 的猜想,并解决了 Vesti 的开放问题。

摘要:

长度为 $n$ 的词若包含 $n$ 个非空回文因子,则称其为富词。若一个无限词的所有有限因子均为富词,则该无限词为富词。Baranwal 和 Shallit 构造了一个临界指数为 $2+\sqrt{2}/2$(约等于 2.707)的无限二元富词,并猜想这是无限二元富词可能达到的最小临界指数(即二元富词的重复阈值为 $2+\sqrt{2}/2$)。本文给出了避免 $14/5$ 次幂(即指数至少为 2.8 的重复)的无限二元富词的结构定理。作为推论,我们证明了二元富词的重复阈值确为 $2+\sqrt{2}/2$,验证了 Baranwal 和 Shallit 的猜想。这解决了 Vesti 关于二元字母表的一个开放问题;该问题对于更大的字母表仍然开放。

英文摘要:

A word of length $n$ is rich if it contains $n$ nonempty palindromic factors. An infinite word is rich if all of its finite factors are rich. Baranwal and Shallit produced an infinite binary rich word with critical exponent $2+\sqrt{2}/2$ ($\approx 2.707$) and conjectured that this was the least possible critical exponent for infinite binary rich words (i.e., that the repetition threshold for binary rich words is $2+\sqrt{2}/2$). In this article, we give a structure theorem for infinite binary rich words that avoid $14/5$-powers (i.e., repetitions with exponent at least 2.8). As a consequence, we deduce that the repetition threshold for binary rich words is $2+\sqrt{2}/2$, as conjectured by Baranwal and Shallit. This resolves an open problem of Vesti for the binary alphabet; the problem remains open for larger alphabets.

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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