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arXiv 1905.01232math.LO
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具有任意间隔的奇异基数的首后继和双后继树性质

The tree property at first and double successors of singular cardinals with an arbitrary gap

Alejandro Poveda

摘要:

设$\mathrm{cof}(μ)=μ$和$κ$是具有$μ<κ$的超紧基数.假设有一个递增的连续基数序列$\langleκ_ξ\mid ξ<μ\rangle$和$κ_0:=κ$,使得对于每个$ξ<μ$,$κ_{ξ+1}$是超紧的。此外,还假设$λ$是一个弱紧基数,且有$\sup_{ξ<μ}κ_ξ<λ$ .令$Θ\geqλ$是具有$\mathrm{cof}(Θ)>κ$的基数。在假定$\mathrm{GCH}_{\geqκ}$的基础上,构造了一个泛延拓,其中$κ$是强极限,$\mathrm{cof}(κ)=μ$,$2^κ= Θ$和$\mathrm{TP}(κ^+)$,$\mathrm{TP}(κ^{++})$都成立.此外,在这个模型中,$κ$有一个非常好的和一个不好的尺度。这推广了[Sin16a]和[FHS18]的主要结果。

英文摘要:

Let $\mathrm{cof}(μ)=μ$ and $κ$ be a supercompact cardinal with $μ<κ$. Assume that there is an increasing and continuous sequence of cardinals $\langleκ_ξ\mid ξ<μ\rangle$ with $κ_0:=κ$ and such that, for each $ξ<μ$, $κ_{ξ+1}$ is supercompact. Besides, assume that $λ$ is a weakly compact cardinal with $\sup_{ξ<μ}κ_ξ<λ$. Let $Θ\geqλ$ be a cardinal with $\mathrm{cof}(Θ)>κ$. Assuming the $\mathrm{GCH}_{\geqκ}$, we construct a generic extension where $κ$ is strong limit, $\mathrm{cof}(κ)=μ$, $2^κ= Θ$ and both $\mathrm{TP}(κ^+)$ and $\mathrm{TP}(κ^{++})$ hold. Further, in this model there is a very good and a bad scale at $κ$. This generalizes the main results of [Sin16a] and [FHS18].

机构、总结、中文摘要均由AI分析而来,可能存在错误,请以论文正文为准。

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